我有两个类,一个是发送者类,另一个是接收者类。发送和接收应用程序都会在几秒钟后停止并关闭。 我的发件人类是:
public class MainActivity extends Activity {
InetAddress receiverAddress;
DatagramSocket datagramSocket;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
try {
datagramSocket = new DatagramSocket(4444);
} catch (SocketException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
byte[] buffer = "0123456789".getBytes();
byte[] address="192.168.1.101".getBytes();
try {
receiverAddress = InetAddress.getByAddress(address);
} catch (UnknownHostException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
DatagramPacket packet = new DatagramPacket(
buffer, buffer.length, receiverAddress, 4444);
try {
datagramSocket.send(packet);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
我的录取课程是:
public class MainActivity extends Activity {
DatagramSocket datagramSocket;
DatagramPacket packet;
TextView tv1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv1=(TextView)findViewById(R.id.textView1);
try {
datagramSocket = new DatagramSocket(80);
} catch (SocketException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
byte[] buffer = new byte[10];
packet = new DatagramPacket(buffer, buffer.length);
try {
datagramSocket.receive(packet);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
byte[] buff = packet.getData();
tv1.setText(buff.toString());
}
提前感谢您的帮助。
答案 0 :(得分:3)
在Android中,您不允许在UIThread(主线程)上执行网络操作
解决此问题: 将您的网络代码复制到新的线程并让它运行。
答案 1 :(得分:1)
“新DatagramSocket(...)”调用中的端口号看起来很奇怪。客户端应该创建一个“未绑定”的套接字 - 只需使用“new DatagramSocket();”。发送方应绑定到客户端发送到的端口,即“new DatagramSocket(4444);”。
答案 2 :(得分:0)
源和目标端口号应相同。在“DatagramSocket(xxx)”中给出相同的数字。两个程序中的xxx必须相同。