如何选择在列中显示更多次数的日期

Question

例如：

表是

date                      bill amount
12/06/2013                  200
12/06/2013                  920
15/06/2013                  300

输出

date                    bill amount
12/06/2013                  1120
15/06/2013                  300

Answer 1

这是SQLFiddle

 SELECT date, SUM(billamount)
   FROM tab1 GROUP BY date;

Answer 2

使用 group by 来实现目标。

Answer 3

SELECT theDate, COUNT(theDate) AS NumOccurrences

FROM someTable GROUP BY theDate

HAVING ( COUNT(theDate) > 1 )

Answer 4

sqlfiddle

select d as "date",
       sum(amount) as "bill amount", 
       count(*) as "count" 
from T
group by d
having count(*) > 0 --change zero to occurrence number you wish
order by d;

sqlfiddle