Question

我需要用多个数组解析JSON文件。数组的格式为：

{
    "List": {
        "Something": [
            {
                "Name": "John",
                "phone": "test"
            }
        ]
        "SomethingElse": [
            {
                "Name": "Smith",
                "phone": "test"
            }
        ]
    }
}

问题是我不知道下一个数组名称是什么。可以解析来自所有数组的数据而无需更改它的结构并且不改变它的结构？

感谢。

Answer 1

JSON

{
"data": {
    "current_condition": [{
        "cloudcover": "25",
        "humidity": "62",
        "observation_time": "04:57 PM",
        "precipMM": "0.1",
        "pressure": "1025",
        "temp_C": "10",
        "temp_F": "50",
        "visibility": "10",
        "weatherCode": "113",
        "weatherDesc": [{
            "value": "Clear"
        }],

获得“weatherDesc”的价值

    private class DownloadJSON extends AsyncTask<Void, Void, Void> {

    @Override
    protected void onPreExecute() {
        super.onPreExecute();
        // Create a progressdialog
        mProgressDialog = new ProgressDialog(MainActivity.this);
        // Set progressdialog title
        mProgressDialog.setTitle("Android JSON Parse Tutorial");
        // Set progressdialog message
        mProgressDialog.setMessage("Loading...");
        mProgressDialog.setIndeterminate(false);
        // Show progressdialog
        mProgressDialog.show();
    }

    @Override
    protected Void doInBackground(Void... params) {
        // Create an array
        arraylist = new ArrayList<HashMap<String, String>>();
        // Retrieve JSON Objects from the given URL address
        jsonobject = JSONfunctions
                .getJSONfromURL("http://api.worldweatheronline.com/free/v1/weather.ashx?q=London&format=json&num_of_days=5&key=8mqumbup9fub7bcjtsxbzxx9");

        try {
            // Locate the array name in JSON
            JSONObject on=jsonobject.getJSONObject("data");
            jsonarray = on.getJSONArray("current_condition");

            for (int i = 0; i < jsonarray.length(); i++) {
                HashMap<String, String> map = new HashMap<String, String>();
                jsonobject = jsonarray.getJSONObject(i);
            JSONArray sen1=jsonobject.getJSONArray("weatherDesc");
                // Retrive JSON Objects
            for(int j=0;j<sen1.length();j++){
                jsonobject2 = sen1.getJSONObject(j);
                map.put("value0", jsonobject2.getString("value"));
                map.put("value1",jsonobject2.getString("value"));

                map.put("flag", null);
                // Set the JSON Objects into the array
                arraylist.add(map);
            }
            }
        } catch (JSONException e) {
            Log.e("Error", e.getMessage());
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(Void args) {
        // Locate the listview in listview_main.xml
        listview = (ListView) findViewById(R.id.listview);
        // Pass the results into ListViewAdapter.java
        adapter = new ListViewAdapter(MainActivity.this, arraylist);
        // Set the adapter to the ListView
        listview.setAdapter(adapter);
        // Close the progressdialog
        mProgressDialog.dismiss();
    }
}

Answer 2

试试这个

我编写了一个函数来递归迭代JsonObject而不知道键名。

private void parseJson(JSONObject data) {

        if (data != null) {
            Iterator<String> it = data.keys();
            while (it.hasNext()) {
                String key = it.next();

                try {
                    if (data.get(key) instanceof JSONArray) {
                        JSONArray arry = data.getJSONArray(key);
                        int size = arry.length();
                        for (int i = 0; i < size; i++) {
                            parseJson(arry.getJSONObject(i));
                        }
                    } else if (data.get(key) instanceof JSONObject) {
                        parseJson(data.getJSONObject(key));
                    } else {
                        System.out.println("" + key + " : " + data.optString(key));
                    }
                } catch (Throwable e) {
                    System.out.println("" + key + " : " + data.optString(key));
                    e.printStackTrace();

                }
            }
        }
    }

Answer 3

Something值之后JSON中缺少逗号，但除此之外，您可以使用任何JSON解析器对其进行解析。

Android JSON解析多个数组

3 个答案: