Question

基本上，我有一个多维数组，我需要构建一个简单的字符串。

相当简单的问题，虽然它已经在我身上吃了很长时间了，因为我似乎无法指出它。

以下是一个示例，说明我的数组在其中只有3个问题的外观：

[["question1","answer1","answer2","answer3","answer4"],["question2","answer1","answer2","answer3","answer4"],["question3","answer1","answer2","answer3","answer4"]]

例如，D.rows[0][0]将是“问题1”而D.rows[2][3]将是“answer3”，只是为了澄清。

以下是必须如何将其保存为字符串：

question1,answer1,answer2,answer3,answer4 
question2,answer1,answer2,answer3,answer4 
question3,answer1,answer2,answer3,answer4

每个元素之间必须有逗号，每个问题必须用换行符分隔。

这是我目前无法正常工作的内容：

var fullString;
for (i = 0; i < csvArray.length; ++i) 
{
    second = secondArray[i];
    for (j = 0; j < second.length; ++j) 
    {
        fullString += entry[j] + "'";
    }
    fullString += "\n";
}

提前致谢！

Answer 1

试试这个

var s,a=[["question1","answer1","answer2","answer3","answer4"],"question2","answer1","answer2","answer3","answer4"],["question3","answer1","answer2","answer3","answer4"]];
for(i=0; i < a.length; i++){
    s=(s)?s+"\n\r"+a[i].join():a[i].join();
}

jsfiddle example

在您自己的示例中：由于您要直接添加到fullString，因此它应该有一个空字符串作为值，否则您最终会得到undefined。

var fullString="";

此部分second = secondArray[i];应该是

var second = csvArray[i];

并且以同样的方式fullString += entry[j] + "'";应该是

fullString += second[j] + ",";

Answer 2

一个班轮：

var result = [["question1","answer1","answer2","answer3","answer4"],["question2","answer1","answer2","answer3","answer4"],["question3","answer1","answer2","answer3","answer4"]].join('\r\n');

Answer 3

类似的东西：

var questionAnswerSet = {“question1”：[
                                    {“answer1”：“价值”，                                       “answer2”：“价值”，                                       “answer3”：值}                                   ]，
                            “问题2”：[
                                    {“answer1”：“价值”，                                       “answer2”：“价值”，                                       “answer3”：值}                                   ]                 }

并像这样访问：

questionAnswerSet [0] .answer2 //提问一个答案2

questionAnswerSet [1] .answer2 //提问2答案2

Answer 4

如果您有一个数组......

var arr = [["question1","answer1","answer2","answer3","answer4"],["question2","answer1","answer2","answer3","answer4"],["question3","answer1","answer2","answer3","answer4"]];

...然后

var strArr  =  arr.join(',');
var strLine =  arr.join('\n'); // string with line breaks.

会为你做到这一点。

如果你想为每个问题 - 答案块设置不同的字符串，那么......

var strJoinArr = [], strJoinLines = '';
for(var i = 0; i < arr.length; i++){
    strJoinArr.push(arr[i].join(','));
    strJoinLines += arr[i].join(',')+ '\n'; // string with line break
}

然后访问每个部分，你可以使用索引，

例如，strJoinArr[2]将返回'question3,answer1,answer2,answer3,answer4'

更多关于.join() 更多关于.push()

Answer 5

for (var i=0; i<yourArray.length; i++) { // iterate on the array
   var obj = yourArray[i];
   for (var key in obj) { // iterate on object properties
      var value = obj[key];
      console.log(value);
   }
}

Answer 6

如果您计划更改分隔符以获得答案数，这可能是您的解决方案。

var array = [["question1","answer1","answer2","answer3","answer4"],["question2","answer1","answer2","answer3","answer4"],["question3","answer1","answer2","answer3","answer4"]],
string = "";

for (var i = 0; i <= array.length - 1; i++) {
     string +=array[i].join(', ');
     string += "\n";
}

此外，对于此结构的任何对象，其可读性较低但也是有效的

string = array.join('\r\n');

如何从多维数组构建一个简单的字符串？

6 个答案: