Question

我正在尝试将变量合并到字典中存在的键中。以下是规则：

如果密钥已存在，则将值计数器递增1。

如果存在与键的部分匹配：   一个。如果变量length小于key但re.search不是None，则将值计数器递增1   湾如果变量长度大于key且re.search不是None，则将key替换为变量并将计数器增加一个

如果此后存在变量但在字典中仍然没有匹配，则将变量添加到字典

我已经能够完成1,2a和2b，但我不知道如何添加3.任何帮助/建议将不胜感激。这是目前形式的剧本：我也希望在Dict中看到“乌龟”。

Animals = ["phant", "eleph", "tiger", "turtle", "zebra", "ostrich"]
Dict = {"horse":1, "elephant":1, "iger":1, "ostrich":1}

for name in Animals:
     if name in Dict:
             Dict[name]=Dict[name]+1
     else:
             for key, val in Dict.items():
                     if len(name) < len(key):
                             m = re.search (name, key)
                             if m != None:
                                     print ("Found match!", name)
                                     Dict[key] = Dict[key] + 1
                                     break
                     elif len(name) > len(key):
                              m = re.search (key, name)
                              if m != None:
                                     print ("Found match!", name)
                                     Dict[name] = Dict.pop(key) + 1
                                     Dict[name] = Dict[name] + 1
                                     break

Answer 1

在查看代码后描述案例＃3的一种方法是“如果break语句都没有执行”。您可以通过在else循环后放置for语句来处理这种情况。只有在for循环运行完成时（或换句话说，循环内没有break语句运行），才会执行此块中的代码：

Animals = ["phant", "eleph", "tiger", "turtle", "zebra", "ostrich"]
Dict = {"horse":1, "elephant":1, "iger":1, "ostrich":1}

for name in Animals:
    if name in Dict:
        Dict[name]=Dict[name]+1
    else:
        for key, val in Dict.items():
            if len(name) < len(key):
                m = re.search (name, key)
                if m != None:
                    print ("Found match!", name)
                    Dict[key] = Dict[key] + 1
                    break
            elif len(name) > len(key):
                m = re.search (key, name)
                if m != None:
                    print ("Found match!", name)
                    Dict[name] = Dict.pop(key) + 1
                    Dict[name] = Dict[name] + 1
                    break
        else:                 # this line and the one below it are new
            Dict[name] = 1

Answer 2

for name in Animals:
    if name in Dict:
        Dict[name]=Dict[name]+1
    else:
        found= False
        for key, val in Dict.items():
            if len(name) < len(key):
                m = re.search (name, key)
                if m != None:
                    print ("Found match!", name)
                    Dict[key] = Dict[key] + 1
                    found= True
                    break
            elif len(name) > len(key):
                m = re.search (key, name)
                if m != None:
                    print ("Found match!", name)
                    Dict[name] = Dict.pop(key) + 1
                    found= True
                    break
        if not found
            Dict[name] = 1

我更喜欢以下内容：

for name in Animals:
    if name in Dict:
        Dict[name]=Dict[name]+1
    else:
        found= False
        for key, val in Dict.items():
            m = re.search (name, key)
            if m != None:
                print ("Found match!", name)
                if len(name) < len(key):
                    Dict[key] = Dict[key] + 1
                else
                    Dict[name] = Dict.pop(key) + 1
                found= True
                break
        if not found
            Dict[name] = 1

Python3中的条件合并

2 个答案: