我有具有None的同类对象列表,但它可以包含任何类型的值。 例如:
>>> l = [1, 3, 2, 5, 4, None, 7]
>>> sorted(l)
[None, 1, 2, 3, 4, 5, 7]
>>> sorted(l, reverse=True)
[7, 5, 4, 3, 2, 1, None]
是否有办法在不重新发明轮子的情况下获取通常用于python方式的列表,但是在列表的末尾没有值,如:
[1, 2, 3, 4, 5, 7, None]
我觉得这里可以使用“key”参数
答案 0 :(得分:79)
>>> l = [1, 3, 2, 5, 4, None, 7]
>>> sorted(l, key=lambda x: (x is None, x))
[1, 2, 3, 4, 5, 7, None]
这为列表中的每个元素构造一个元组,如果值为None
,则元组为(True, None)
,如果值为其他任何值,则为(False, x)
(其中{ {1}}是值)。由于元组是逐项排序的,这意味着所有非x
元素将首先出现(从None
开始),然后按值排序。
答案 1 :(得分:14)
试试这个:
sorted(l, key=lambda x: float('inf') if x is None else x)
由于无穷大大于所有整数,None
将始终放在最后。
答案 2 :(得分:0)
我创建了一个功能,扩展了Andrew Clark和tutuDajuju的评论。
def sort(myList, reverse = False, sortNone = False):
"""Sorts a list that may or may not contain None.
Special thanks to Andrew Clark and tutuDajuju for how to sort None on https://stackoverflow.com/questions/18411560/python-sort-list-with-none-at-the-end
reverse (bool) - Determines if the list is sorted in ascending or descending order
sortNone (bool) - Determines how None is sorted
- If True: Will place None at the beginning of the list
- If False: Will place None at the end of the list
- If None: Will remove all instances of None from the list
Example Input: sort([1, 3, 2, 5, 4, None, 7])
Example Input: sort([1, 3, 2, 5, 4, None, 7], reverse = True)
Example Input: sort([1, 3, 2, 5, 4, None, 7], reverse = True, sortNone = True)
Example Input: sort([1, 3, 2, 5, 4, None, 7], sortNone = None)
"""
return sorted(filter(lambda item: True if (sortNone != None) else (item != None), myList),
key = lambda item: (((item is None) if (reverse) else (item is not None)) if (sortNone) else
((item is not None) if (reverse) else (item is None)), item),
reverse = reverse)
以下是如何运行它的示例:
myList = [1, 3, 2, 5, 4, None, 7]
print(sort(myList))
print(sort(myList, reverse = True))
print(sort(myList, sortNone = True))
print(sort(myList, reverse = True, sortNone = True))
print(sort(myList, sortNone = None))
print(sort(myList, reverse = True, sortNone = None))