我有以下格式: Value1为{0},Value2为{1}。
我需要用字符串替换括号中的数字。这在大多数语言中都可以使用string.Format或其他类似的东西轻松完成。我怎么能只使用vbscript呢?
我试过了:
Replace (strFormat, "{0}", value1)
Replace (strFormat, "{1}", value2)
它不起作用。任何解决方案?
答案 0 :(得分:10)
我想要类似的东西并且不喜欢这些答案,因为它们意味着每个值有多行(忽略Beaner的答案是错误的语言!)所以我创建了以下内容:
Public Function StrFormat(FormatString, Arguments())
Dim Value, CurArgNum
StrFormat = FormatString
CurArgNum = 0
For Each Value In Arguments
StrFormat = Replace(StrFormat, "{" & CurArgNum & "}", Value)
CurArgNum = CurArgNum + 1
Next
End Function
您可以使用以下(请注意,您需要在变量周围添加“Array()”):
formatString = "Test '{0}', '{2}', '{1}' and {0} again!"
Response.Write StrFormat(formatString, Array(1, 2, "three", "Unused"))
Response.Write StrFormat(formatString, Array(4, 5, "six", "Unused"))
将输出您期望的内容:
Test '1', 'three', '2' and 1 again!
Test '4', 'six', '5' and 4 again!
希望这对其他语言的人来说更自然。
答案 1 :(得分:9)
Replace (strFormat, "{0}", value1)
根据你的代码片段,我猜你直接认为替换mutate strFormat
。它不像那样工作;您可以将结果分配给原始变量,如下所示:
strFormat = Replace (strFormat, "{0}", value1)
您还可以指定另一个变量来存储更改的结果,如下所示:
strFormat2 = Replace (strFormat, "{0}", value1)
答案 2 :(得分:4)
至于无的答案到目前为止解决了格式化的问题(相反) 将字符串插入/拼接成字符串):
这个简单的类:
Class cFormat
Private m_oSB
Private Sub Class_Initialize()
Set m_oSB = CreateObject("System.Text.StringBuilder")
End Sub ' Class_Initialize
Public Function formatOne(sFmt, vElm)
m_oSB.AppendFormat sFmt, vElm
formatOne = m_oSB.ToString()
m_oSB.Length = 0
End Function ' formatOne
Public Function formatArray(sFmt, aElms)
m_oSB.AppendFormat_4 sFmt, (aElms)
formatArray = m_oSB.ToString()
m_oSB.Length = 0
End Function ' formatArray
End Class ' cFormat
通过COM利用.NET格式化VBScript。现在你可以做到:
-------- Interpolation
Use |Value1 is {0} and Value2 is {1}.|
to get |Value1 is zero and Value2 is one.|
from |zero one|
Use |{0} x 2 => {0}{0}|
to get |once x 2 => onceonce|
from |once|
-------- Cherrypicking
Use |{6,4}: [{0}, {2}, {4}]|
to get |even: [0, 2, 4]|
from |0 1 2 3 4 5 even odd|
Use |{7,4}: [{5}, {3}, {1}]|
to get | odd: [5, 3, 1]|
from |0 1 2 3 4 5 even odd|
-------- Conversions
Use ||{0:D}| |{0:X}| |{0:N3}| |{0:P2}| (german locale!)|
to get ||123| |7B| |123,000| |12.300,00%| (german locale!)|
from |123|
Use ||{0}| |{0:U}| |{0:u}||
to get ||29.06.2012 14:50:30| |Freitag, 29. Juni 2012 12:50:30| |2012-06-29 14:50:30Z||
from |29.06.2012 14:50:30|
Use ||{0}| |{0:E1}| |{0:N1}| |{0:N2}| |{0:N3}||
to get ||1234,56| |1,2E+003| |1.234,6| |1.234,56| |1.234,560||
from |1234,56|
-------- Alignment
Use ||{0,1:D}| |{0,2:D}| |{0,-2:D}| |{0,5:D}| |{0,-5:D}||
to get ||12| |12| |12| | 12| |12 ||
from |12|
如果您对测试/演示脚本感兴趣,可以进行一些实验 属于你自己:
Option Explicit
' Class cFormat ...
Dim oFormat : Set oFormat = New cFormat
Dim aTests : aTests = Array( _
Array("Interpolation" _
, Array( _
Array(True, "Value1 is {0} and Value2 is {1}.", Array("zero", "one")) _
, Array(False, "{0} x 2 => {0}{0}" , "once" ) _
} _
) _
, Array("Cherrypicking" _
, Array( _
Array(True , "{6,4}: [{0}, {2}, {4}]", Array(0, 1, 2, 3, 4, 5, "even", "odd")) _
, Array(True , "{7,4}: [{5}, {3}, {1}]", Array(0, 1, 2, 3, 4, 5, "even", "odd")) _
} _
) _
, Array("Conversions" _
, Array( _
Array(False, "|{0:D}| |{0:X}| |{0:N3}| |{0:P2}| (german locale!)", 123 ) _
, Array(False, "|{0}| |{0:U}| |{0:u}|" , Now ) _
, Array(False, "|{0}| |{0:E1}| |{0:N1}| |{0:N2}| |{0:N3}|" , 1234.56 ) _
} _
) _
, Array("Alignment" _
, Array( _
Array(False, "|{0,1:D}| |{0,2:D}| |{0,-2:D}| |{0,5:D}| |{0,-5:D}|", 12 ) _
} _
) _
)
Dim sFormat : sFormat = "Use |{0}|{3}to get |{1}|{3}from |{2}|{3}"
Dim aData : aData = Array(0, 1, 2, vbCrLf)
Dim aTest
For Each aTest In aTests
WScript.Echo "--------", aTest(0)
Dim aSample
For Each aSample In aTest(1)
aData(0) = aSample(1)
If aSample(0) Then
aData(1) = oFormat.formatArray(aSample(1), aSample(2))
aData(2) = Join(aSample(2))
Else
aData(1) = oFormat.formatOne( aSample(1), aSample(2))
aData(2) = aSample(2)
End If
WScript.Echo oFormat.formatArray(sFormat, aData)
Next
WScript.Echo
Next
要了解.NET中的格式,请从StringBuilder.AppendFormat Method (String, Object)和Formatting Types开始。
答案 3 :(得分:0)
为什么不呢?这段代码在这里工作:
value1 = "1"
value2 = "2"
strFormat = "Value1 is {0} and Value2 is {1}."
strFormat = Replace (strFormat, "{0}", value1)
strFormat = Replace (strFormat, "{1}", value2)
MsgBox strFormat
注意我为每次替换更新了strFormat
值。
如果您需要更灵活的实现,可以使用正则表达式,但现在似乎不需要。
答案 4 :(得分:0)
这是一个很好的小函数,它的工作方式类似于.NET string.Format函数。我很快就这样做了,所以添加错误处理取决于你。我在VB6中做了这个并添加了对 Microsoft VBScript正则表达式5.5 的引用
Public Function StringFormat(ByVal SourceString As String, ParamArray Arguments() As Variant) As String
Dim objRegEx As RegExp ' regular expression object
Dim objMatch As Match ' regular expression match object
Dim strReturn As String ' the string that will be returned
Set objRegEx = New RegExp
objRegEx.Global = True
objRegEx.Pattern = "(\{)(\d)(\})"
strReturn = SourceString
For Each objMatch In objRegEx.Execute(SourceString)
strReturn = Replace(strReturn, objMatch.Value, Arguments(CInt(objMatch.SubMatches(1))))
Next objMatch
StringFormat = strReturn
End Function
示例:的
StringFormat(“你好{0}。我希望你见{1}。他们都适用于{2}。{0}已经为{2}工作了15年。”,“布鲁斯”,“克里斯“,”凯尔“)
返回:
你好布鲁斯。我希望你能见到克里斯。他们都为凯尔工作。布鲁斯在凯尔工作了15年。