Groupby使用PIVOT

Question

我有这张桌子：

Person  Job
PersonA XX
PersonA XX
PersonA XX
PersonB XX
PersonB XX
PersonB YY
PersonB ZZ
PersonC XX
PersonC XX
PersonA XX
PersonA YY
PersonB ZZ
...

现在，我希望输出是这样的：

Job PersonA PersonB Person C
XX  4       2       2
YY  1       1       0
ZZ  0       2       0

到目前为止，我有这个：

SELECT DISTINCT Person,
                       (SELECT COUNT(Job)
                        FROM dbo.TableName
                        GROUP BY Job)
FROM dbo.ExcelImport

没有运气:(

Answer 1

你应该尝试这样的事情：

select
    Job
    ,SUM(case when Person = 'PersonA'
        then
            1
        else
            0
    end) as 'PersonA'
    ,SUM(case when Person = 'PersonB'
        then
            1
        else
            0
    end) as 'PersonB'
    ,SUM(case when Person = 'PersonC'
        then
            1
        else
            0
    end) as 'PersonC'
from
    TableName
group by
    Job

Answer 2

pivot运营商很容易完成任务：

select *
from (select Job as Job2, * from [TableName]) t
    pivot (count(Job2) for Person in ([PersonA],[PersonB],[PersonC])) p

Answer 3

你也可以使用支点

select * from per
pivot (count(job)  for job in ([xx],[yy],[zz]))

Answer 4

如果有人被修复，请尝试此操作

SELECT * FROM Table1
PIVOT
(
    COUNT([Person]) FOR [Person] IN ([PersonA],[PersonB],[PersonC])
) p

SQL FIDDLE DEMO

如果有不同的人，请尝试此动态查询

DECLARE @cols AS NVARCHAR(MAX), @query  AS NVARCHAR(MAX)
SELECT @cols = STUFF((SELECT distinct ',' + QUOTENAME([Person]) 
                    from Table1
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

SET @query = 'SELECT [Job],' + @cols + ' 
             FROM
             (
                Select *
                FROM Table1
             ) T
             PIVOT
             (
                COUNT([Person])
                FOR [Person] IN (' + @cols + ')
             ) pvt '

EXECUTE(@query);