在我的py脚本中,我需要将数据写入csv文件,每行结果为五列。
title:info title title title title
one two three four five
one two three four five
title:info title title title title
one two three four five
我想使用file.write()
方法,而不是csv模块,如果可能的话。
for ip in open("list.txt"):
with open("data.txt", "a") as csv_file:
csv_file.write("\r Title:" + ip + ", Title, Title, Title, Title \r")
for line in open("0820-oRG-apflog.txt"):
new_line = line.split()
#search apflog for correct lines
if "blocked" in new_line:
if "src="+ip.strip() in new_line:
#write columns to new text file & remove headers from lines in files and add commas
csv_file.write(ip + ", " + new_line[11].replace("dst=", ", ") + new_line[12].replace("proto=", ", "))
try:
csv_file.write(new_line[14].replace("dpt=", ", "))
except IndexError:
pass
当我运行脚本时,我得到了结果:
title:info
title title title title
one
two three four five
我尝试过:csv_file.write('%r\n%r\n%r\n' % (one, three, four))
和变体,但数据并没有按照我需要的方式运行。
我不知道我的代码在哪里出错了。我认为.write()
会将数据写入同一行,除非另有说明(以前的用途)。
问题:我如何.write()
将一行模式划分为一个csv行,并将模式分成不同的行?
谢谢!
答案 0 :(得分:1)
从首先读取的行中删除尾部换行符。