Question

当我尝试解析像＆＃34; care＆amp; love＆＃34;这样的特殊字符时，它只显示＆＃34; care＆＃34;，＆＃34;＆amp;＆＃34;之后的部分。截断我怎么能让它显示完整的字符串???

NSURL *url = [NSURL URLWithString:urlStr];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url  cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];

NSString *postJson = [NSString stringWithFormat:@"&json=%@", jsonRequest];

NSData *requestData = [postJson dataUsingEncoding:NSUTF8StringEncoding];

[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

Answer 1

您可以使用Cocoa's built-in JSON serialization。这将排除不正确的字符串转义（这很可能是您当前代码中的问题）。

示例：

NSError* error = nil;
NSDictionary* jsonDict = @{@"json": @"EL- STR 261: HAUL & SPOT"};
NSData* requestData = [NSJSONSerialization dataWithJSONObject:jsonDict options:kNilOptions error:&error];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"content-type"];
[request setValue:[NSString stringWithFormat:@"%d", [requestData length]]  forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody: requestData];

Answer 2

假设我们正在谈论jsonRequest的值，你必须在将该字符串传递给postJson之前对其进行URL编码，否则＆amp;被视为参数分隔符。

json = care＆amp; love被接收服务器解释为json =“care”和love =“”。

编码该值的网址将类似于json = love％26care，并将由服务器解码为json =“love＆amp; care”

使用stringByAddingPercentEscapesUsingEncoding进行转义，请参阅：https://developer.apple.com/library/mac/documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html#//apple_ref/occ/instm/NSString/stringByAddingPercentEscapesUsingEncoding：

解析特殊字符问题

2 个答案: