Question

我为一个类型做了一个计数器，一切正常，但有一个问题。

有两种不同的类型。我只想要1种类型的数量而不是两者。类型1 =电影 type 2 = tvshow

$genre_list = array('Action','Adult','Adventure','Animation','Biography','Bollywood','Comedy','Crime','Documentary','Drama','Family','Fantasy','History','Horror','Musical','Mystery','Reality-TV','Sci-Fi','Sport','Thriller','War','Western');
$query_parts = array();
foreach ($genre_list as $genre) {
    $query_parts[] = "'%".mysql_real_escape_string($genre)."%'";
}

$string = implode(' OR genre LIKE ', $query_parts);
$tank = mysql_query("SELECT genre FROM `topmovies`.`movies` WHERE type='tvshow' AND genre LIKE {$string} GROUP BY name");

while( $fetch = mysql_fetch_array( $tank ) ){

        $count = explode(', ', $fetch['genre']);

        foreach( $count as $w)
            if( in_array($w, $genre_list) )
                $query_parts[$w]++;

}

如你所见，我想计算所有类型为'tvshow'的游戏类型，但问题是，它也会计算“电影”类型的类型！

我真的没有弄错..

Answer 1

变化 AND genre LIKE {$string} 至 AND (genre LIKE {$string})

当前查询形式如：

（type ='tvshow'AND genre LIKE“a”）或类型如“b”** ....

php mysql计数器不起作用

1 个答案: