Question

Google未对我网站的代码或说明编制索引，并根据网址生成自己的代码或说明。

以下是搜索结果的链接： https://www.google.com/#fp=771e16ed773001d1&q=mediatree&safe=off

此外，这是HTML标题。

    <!DOCTYPE HTML PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">

    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <meta name="description" content="Since 1995, MediaTree has been the leader in providing both innovative promotions and flexible solutions that are designed to motivate and reward consumer behavior. MediaTree's promotional strategies help drive performance and increase brand loyalty by offering recipients the latest in digital promotions and cutting-edge incentives. From Music Downloads to Movie Tickets there's a reward to fit any demographic or industry. ">
<title>MediaTree: Custom Branded Music Download, Movie Ticket, Magazine Subscription Cards and more!</title>

        <!-- CSS -->

    ...

Answer 1

您的http://www.mediatreegroup.com/robots.txt文件说明了这一点：

User-agent: *
Disallow: /

这基本上告诉搜索引擎他们不应该访问网站上的任何页面 - 因此Google服从并且不访问页面，因此不会阅读您的元描述。

见这里：The Web Robots Pages

尽快改变这一点：

User-agent: *
Disallow:

如果您希望搜索引擎抓取所有内容，或者RTM以找出您实际上应该禁止的内容。

我的网站的Google索引问题

1 个答案: