我有一个小脚本,取决于时间和日期;我希望它输出不同的东西:
<?php
$currenttime = ((date("H")+7). ":" .date("i"));
if ($currenttime >= "16:30") {
$tomorrow = mktime(0, 0, 0, date("m") , date("d")+2, date("Y"));
$jsdate = (date("Y"). "-" .date("m"). "-" .(date("d")+1). "-16-30");
}
else{
$tomorrow = mktime(0, 0, 0, date("m") , date("d")+1, date("Y"));
$jsdate = (date("Y"). "-" .date("m"). "-" .date("d"). "-16-30");
}
echo " Time left for delivery on <b><center>" .date("l \\t\h\e jS F", $tomorrow). "</b>:</center>";
?>
<center>
<script>
// deadline(date, width, height, style, background, number color, small text color);
deadline("<? echo $jsdate; ?>", "220", "37", "digital2", "#FFFFFF", "#000099", "#000000");
</script>
</center>
例如,在16:30之前的星期一,它需要以下内容:
然后在星期一16:30之后需要阅读:
然后从周四16:30到周一16:30,需要阅读:
我希望这一切都有意义,谢谢你们。
钽, 乙
答案 0 :(得分:1)
您可以使用strtotime和(php 5.3+)类DateTime来创建,比较和格式化时间戳和间隔。
e.g。 (既没有真正测试也没有完全你所描述的格式):
<?php
$now = new DateTime();
$deliveries = array(
'monday' => strtotime('monday 16:30'),
'tuesday' => strtotime('tuesday 16:30')
);
// timestamps in the past are "advanced" one week
foreach($deliveries as &$dt) {
if ( $dt < $now->getTimestamp() ) {
$dt = strtotime('+1 week', $dt);
}
}
// get the diff between 'Now' and the next delivery (smallest timestamp in $deliveries)
$nextDelivery = new DateTime();
$nextDelivery->setTimestamp( min($deliveries) );
$remaining = $nextDelivery->diff($now);
echo $nextDelivery->format(DateTime::RFC2822), " | ", $remaining->format('%d days %H:%i:%S'), "\n";
编辑:不使用DateTime:
<?php
$now = time();
$deliveries = array(
'monday' => strtotime('monday 16:30', $now),
'tuesday' => strtotime('tuesday 16:30', $now)
);
// timestamps in the past are "advanced" one week
foreach($deliveries as &$dt) {
if ( $dt < $now) {
$dt = strtotime('+1 week', $dt);
}
}
// get the diff between 'Now' and the next delivery (smallest timestamp in $deliveries)
$nextDelivery = min($deliveries);
// (when) a day has exactly 86400 seconds, an hour 3600 seconds, ...
$remaining = array(
'days'=> intval(($nextDelivery - $now) / 86400),
'hours'=> intval( ($nextDelivery - $now) / 3600) % 24,
'minutes'=> intval( ($nextDelivery - $now) / 60) % 60,
'seconds'=> ($nextDelivery - $now) % 60
);
echo 'next: ', date(DateTime::RFC2822, $nextDelivery), "\n";
printf('remaining: %d days %02d:%02d:%02d',
$remaining['days'], $remaining['hours'], $remaining['minutes'], $remaining['seconds']);
答案 1 :(得分:0)
没有修复你的程序,但这一行
$jsdate = (date("Y"). "-" .date("m"). "-" .date("d"). "-16-30");
可以很容易
$jsdate = date("Y-m-d-16-30");
它更具可读性。