Question

我对在Node.js中读取文件感到很困惑。

fs.open('./start.html', 'r', function(err, fileToRead){
    if (!err){
        fs.readFile(fileToRead, {encoding: 'utf-8'}, function(err,data){
            if (!err){
            console.log('received data: ' + data);
            response.writeHead(200, {'Content-Type': 'text/html'});
            response.write(data);
            response.end();
            }else{
                console.log(err);
            }
        });
    }else{
        console.log(err);
    }
});

文件start.html与尝试打开并阅读它的文件位于同一目录中。

然而，在控制台我得到：

{[错误：ENOENT，打开'./start.html']错误：34，代码：'ENOENT'，路径：'。/ start.html'}

有什么想法吗？

Answer 1

使用path.join(__dirname, '/start.html');

var fs = require('fs'),
    path = require('path'),    
    filePath = path.join(__dirname, 'start.html');

fs.readFile(filePath, {encoding: 'utf-8'}, function(err,data){
    if (!err) {
        console.log('received data: ' + data);
        response.writeHead(200, {'Content-Type': 'text/html'});
        response.write(data);
        response.end();
    } else {
        console.log(err);
    }
});

感谢dc5。

Answer 2

使用Node 0.12，现在可以同步执行此操作：

  var fs = require('fs');
  var path = require('path');

  // Buffer mydata
  var BUFFER = bufferFile('../public/mydata.png');

  function bufferFile(relPath) {
    return fs.readFileSync(path.join(__dirname, relPath)); // zzzz....
  }

fs是文件系统。如果你问的话，readFileSync()会返回一个Buffer或字符串。

fs正确地假设相对路径是安全问题。 path是一种解决方法。

要以字符串形式加载，请指定编码：

return fs.readFileSync(path,{ encoding: 'utf8' });

Answer 3

1）。对于ASync：

var fs = require('fs');
fs.readFile(process.cwd()+"\\text.txt", function(err,data)
            {
                if(err)
                    console.log(err)
                else
                    console.log(data.toString());
            });

2）。对于同步：

var fs = require('fs');
var path = process.cwd();
var buffer = fs.readFileSync(path + "\\text.txt");
console.log(buffer.toString());

Answer 4

使用http模块从服务器读取html文件。这是从服务器读取文件的一种方法。如果要在控制台上获取它，只需删除http模块声明。

var http = require('http');
var fs = require('fs');
var server = http.createServer(function(req, res) {
  fs.readFile('HTMLPage1.html', function(err, data) {
    if (!err) {
      res.writeHead(200, {
        'Content-Type': 'text/html'
      });
      res.write(data);
      res.end();
    } else {
      console.log('error');
    }
  });
});
server.listen(8000, function(req, res) {
  console.log('server listening to localhost 8000');
});

<html>

<body>
  <h1>My Header</h1>
  <p>My paragraph.</p>
</body>

</html>

Answer 5

运行此代码，它将从文件中获取数据并在控制台中显示

function fileread(filename){

    var contents= fs.readFileSync(filename);
    return contents;
}

var fs =require("fs");  // file system

var data= fileread("abc.txt");
//module.exports.say =say;
//data.say();
console.log(data.toString());

Answer 6

var fs = require('fs');
var path = require('path');

exports.testDir = path.dirname(__filename);
exports.fixturesDir = path.join(exports.testDir, 'fixtures');
exports.libDir = path.join(exports.testDir, '../lib');
exports.tmpDir = path.join(exports.testDir, 'tmp');
exports.PORT = +process.env.NODE_COMMON_PORT || 12346;

// Read File
fs.readFile(exports.tmpDir+'/start.html', 'utf-8', function(err, content) {
  if (err) {
    got_error = true;
  } else {
    console.log('cat returned some content: ' + content);
    console.log('this shouldn\'t happen as the file doesn\'t exist...');
    //assert.equal(true, false);
  }
});

Answer 7

如果您想知道如何在目录中读取文件并使用该文件执行某些操作，请继续。这也显示了如何通过power shell运行命令。这是在TypeScript中！我对此有麻烦，所以希望有一天能对某人有所帮助。如果您认为这样对我无济于事，请随时对我投反对票。这对我来说是在某个文件夹内的每个目录中webpack的所有.ts文件，为部署做好了准备。希望您可以使用它！

import * as fs from 'fs';
let path = require('path');
let pathDir = '/path/to/myFolder';
const execSync = require('child_process').execSync;

let readInsideSrc = (error: any, files: any, fromPath: any) => {
    if (error) {
        console.error('Could not list the directory.', error);
        process.exit(1);
    }

    files.forEach((file: any, index: any) => {
        if (file.endsWith('.ts')) {
            //set the path and read the webpack.config.js file as text, replace path
            let config = fs.readFileSync('myFile.js', 'utf8');
            let fileName = file.replace('.ts', '');
            let replacedConfig = config.replace(/__placeholder/g, fileName);

            //write the changes to the file
            fs.writeFileSync('myFile.js', replacedConfig);

            //run the commands wanted
            const output = execSync('npm run scriptName', { encoding: 'utf-8' });
            console.log('OUTPUT:\n', output);

            //rewrite the original file back
            fs.writeFileSync('myFile.js', config);
        }
    });
};

// loop through all files in 'path'
let passToTest = (error: any, files: any) => {
    if (error) {
        console.error('Could not list the directory.', error);
        process.exit(1);
    }

    files.forEach(function (file: any, index: any) {
        let fromPath = path.join(pathDir, file);
        fs.stat(fromPath, function (error2: any, stat: any) {
            if (error2) {
                console.error('Error stating file.', error2);
                return;
            }

            if (stat.isDirectory()) {
                fs.readdir(fromPath, (error3: any, files1: any) => {
                    readInsideSrc(error3, files1, fromPath);
                });
            } else if (stat.isFile()) {
                //do nothing yet
            }

        });
    });
};

//run the bootstrap
fs.readdir(pathDir, passToTest);

Answer 8

与节点的简单同步方式：

let fs = require('fs')

let filename = "your-file.something"

let content = fs.readFileSync(process.cwd() + "/" + filename).toString()

console.log(content)

Answer 9

简单易用：

 const Store = require('data-store');
 const store = new Store({ path: 'filepath/file.json' });

阅读：

     store.get('keyname');

用于更新：

     store.set('keyname',value);

在Node.js中读取文件

9 个答案: