答案 0 :(得分:4)
你可以这样做:
Http Post:
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://blahblah.blah/index.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
nameValuePairs.add(new BasicNameValuePair("command", "make"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
Http Get
HttpResponse response = null;
try {
// Create http client object to send request to server
HttpClient client = new DefaultHttpClient();
// Create URL string
String URL = "http://blahblah.blah/index.php?command=make";
// Create Request to server and get response
HttpGet httpget= new HttpGet();
httpget.setURI(new URI(URL));
response = client.execute(httpget);
} catch (URISyntaxException e) {
e.printStackTrace();
}
catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
答案 1 :(得分:1)
您只需将URL设置为使用URL连接时的URL
即可// you can pass mUrl as http://blahblah.blah/index.php?command=make and if you are expecting a returned value, you can compare that with successVal
public static boolean checkSuccess(String mUrl, String successVal)
{
InputStream is = null;
try
{
URL url = new URL(mUrl);
URLConnection ucon = url.openConnection();
ucon.setConnectTimeout(5000);
ucon.setReadTimeout(5000);
is = ucon.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is, 8192);
ByteArrayBuffer baf = new ByteArrayBuffer(300);
int current = 0;
while ((current = bis.read()) != -1)
{
baf.append((byte) current);
}
String success = new String(baf.toByteArray());
return success.equals(successVal);
}
catch (Exception e)
{
return false;
}
finally
{
try
{
if (is != null)
{
is.close();
}
}
catch (Exception e)
{
}
}
}