Question

美好的一天，

将函数从C＃转换为VB.NET时遇到了一些问题。这是代码：

    public static IEnumerable<string> Lexicograph(List<string> characters, int length)
    {
        for (int i = 0; i < characters.Count; i++)
        {
            if (length == 1)
                yield return characters[i];

            else
                foreach (string nxt in Lexicograph(characters.GetRange(i + 1, characters.Count - (i + 1)), length - 1))
                    yield return characters[i] + " " + nxt;
        }
    }

我知道有一些在线转换器，但由于编译器说我的代码中存在错误/警告（从String转换为IEnumerable），因此这些转换器无法正常工作。

我不熟悉列表和IEnumerable接口，这就是我来到这里的原因。

如果有人可以为此或任何其他类型的小费找到解决方案，我们将不胜感激。

提前致谢。

Answer 1

如果您使用的是Visual Studio 2012：

Public Shared Iterator Function Lexicograph(characters As List(Of String), length As Integer) As IEnumerable(Of String)
    For i = 0 To characters.Count - 1
        If length = 1 Then
            Yield characters(i)
        Else
            For Each nxt In Lexicograph(characters.GetRange(i + 1, characters.Count - (i + 1)), length - 1)
                Yield characters(i) & " " & nxt
            Next
        End If
    Next
End Function

如果您使用的是较旧的版本，并且如果您使用的是非懒惰版本，那么

Public Shared Function LexicographNonLazy(characters As List(Of String), length As Integer) As IEnumerable(Of String)
    Dim result = new List(Of String)
    For i = 0 To characters.Count - 1
        If length = 1 Then
            result.Add(characters(i))
        Else
            For Each nxt In Lexicograph(characters.GetRange(i + 1, characters.Count - (i + 1)), length - 1)
                result.Add(characters(i) & " " & nxt)
            Next
        End If
    Next
    Return result
End Function

Answer 2

试试这个：

Public Shared Iterator Function Lexicograph(ByVal characters As List(Of String), ByVal length As Integer) As IEnumerable(Of String)
        For i As Integer = 0 To characters.Count - 1
            If length = 1 Then
                Yield characters(i)

            Else
                For Each nxt As String In Lexicograph(characters.GetRange(i + 1, characters.Count - (i + 1)), length - 1)
                    Yield characters(i) & " " & nxt
                Next nxt
            End If
        Next i
 End Function

Answer 3

试试这个代码..想想它可以解决..

修改

Public Shared Function Lexicograph(characters As List(Of String), length As Integer) As IEnumerable(Of String) For i As Integer = 0 To characters.Count - 1 If length = 1 Then yield Return characters(i) Else For Each nxt As String In Lexicograph(characters.GetRange(i + 1, characters.Count - (i + 1)), length - 1) yield Return characters(i) + " " & nxt Next End If Next End Function

使用：Code Translator C# to VB
转换

C＃到VB.NET代码转换

3 个答案: