使用android
中的客户经理获取所有者用户名和电话号码这是我的代码..
public void OwnerInfo() {
final AccountManager manager = AccountManager.get(this);
final Account[] accounts = manager.getAccountsByType("com.google");
final int size = accounts.length;
String[] names = new String[size];
for (int i = 0; i < size; i++) {
names[i] = accounts[i].name;
}
if (names[0] != null) {
accountName = names[0];
ContentResolver cr = this.getContentResolver();
Cursor emailCur = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Email.DATA + " = ?",
new String[] { accountName }, null);
while (emailCur.moveToNext()) {
id = emailCur
.getString(emailCur
.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
email = emailCur
.getString(emailCur
.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
String newName = emailCur
.getString(emailCur
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (name == null || newName.length() > name.length())
name = newName;
Log.v("Got contacts", "ID " + id + " Email : " + email
+ " Name : " + name);
}
emailCur.close();
if (id != null) {
// get the phone number
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID
+ " = ?", new String[] { id }, null);
while (pCur.moveToNext()) {
phone = pCur
.getString(pCur
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Log.v("Got contacts", "phone" + phone);
}
pCur.close();
}
}
}
但它显示错误..
08-22 11:47:36.392: E/AndroidRuntime(434): FATAL EXCEPTION: main
08-22 11:47:36.392: E/AndroidRuntime(434): java.lang.ArrayIndexOutOfBoundsException
08-22 11:47:36.392: E/AndroidRuntime(434): at com.param.calltracker.SettingsActivity.OwnerInfo(SettingsActivity.java:142)
08-22 11:47:36.392: E/AndroidRuntime(434): at com.param.calltracker.SettingsActivity$1.onClick(SettingsActivity.java:78)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.view.View.performClick(View.java:2485)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.view.View$PerformClick.run(View.java:9080)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.os.Handler.handleCallback(Handler.java:587)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.os.Handler.dispatchMessage(Handler.java:92)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.os.Looper.loop(Looper.java:123)
08-22 11:47:36.392: E/AndroidRuntime(434): at android.app.ActivityThread.main(ActivityThread.java:3683)
08-22 11:47:36.392: E/AndroidRuntime(434): at java.lang.reflect.Method.invokeNative(Native Method)
08-22 11:47:36.392: E/AndroidRuntime(434): at java.lang.reflect.Method.invoke(Method.java:507)
08-22 11:47:36.392: E/AndroidRuntime(434): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839)
08-22 11:47:36.392: E/AndroidRuntime(434): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597)
08-22 11:47:36.392: E/AndroidRuntime(434): at dalvik.system.NativeStart.main(Native Method)
我的代码中的错误在哪里..请帮助我..
答案 0 :(得分：0)
此代码将为所有者提供完整信息
试试这个代码： -
public class EmailFetcher {
static String getName(Context context) {
Cursor CR=null;
CR=getOwner(context);
String id="",name="";
while (CR.moveToNext()) {
name = CR
.getString(CR
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
}
return name;
}
static String getEmailId(Context context) {
Cursor CR=null;
CR=getOwner(context);
String id="",email="";
while (CR.moveToNext()) {
id = CR.getString(CR
.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
email = CR
.getString(CR
.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
}
return email;
}
static Cursor getOwner(Context context) {
String accountName = null;
Cursor emailCur=null;
AccountManager accountManager = AccountManager.get(context);
Account[] accounts = accountManager.getAccountsByType("com.google");
if (accounts[0].name != null) {
accountName = accounts[0].name;
String where = ContactsContract.CommonDataKinds.Email.DATA + " = ?";
ArrayList<String> what = new ArrayList<String>();
what.add(accountName);
Log.v("Got account", "Account " + accountName);
for (int i = 1; i < accounts.length; i++) {
where += " or " + ContactsContract.CommonDataKinds.Email.DATA + " = ?";
what.add(accounts[i].name);
Log.v("Got account", "Account " + accounts[i].name);
}
String[] whatarr = (String[]) what.toArray(new String[what.size()]);
ContentResolver cr = context.getContentResolver();
emailCur = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
where,
whatarr, null);
/* if (id != null) {
// get the phone number
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID
+ " = ?", new String[]{id}, null);
while (pCur.moveToNext()) {
phone = pCur
.getString(pCur
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
Log.v("Got contacts", "phone" + phone);
}
pCur.close();
}*/
}
return emailCur;
}
}
答案 1 :(得分：-2)
这对你有很大帮助.........
获取手机号码：
How to get the mobile number of current sim card in real device?
获取用户名： How can I get the google username on Android?
尝试在真实设备中运行它....