Question

我正在尝试从“/usr/local/apache/conf/httpd.conf”导出域名，文件中的域名如下所示：

ServerName www.site.com
ServerName www2.site.org

我试图使用：

cat /usr/local/apache/conf/httpd.conf | grep ServerName

但输出将包含：

# ServerName allows you to set a host name which is sent back to clients for
ServerName www.site.com
# to the server the response is coming from) it will use ServerName and
#    ServerName host.some_domain.com
# ServerName allows you to set a host name which is sent back to clients for
ServerName www2.site.org
# to the server the response is coming from) it will use ServerName and
#    ServerName host.some_domain.com

Answer 1

尝试

grep '^ServerName' /usr/local/apache/conf/httpd.conf

这是有效的，因为grep在模式中接受regular expressions。 ^是任何一行的起始位置。

此外，请勿使用cat将文件传递到grep之类的内容，因为grep有文件名参数。

Answer 2

尝试awk

awk 'BEGIN{count=0;print "Text at top";}/ServerName/ {count++;if(count == 1){print "Text  
between two ServerName", count}}END{print "Text at the end"}' /usr/local/apache
/conf/httpd.conf

使用您自己的文本替换print语句中的文本。

BEGIN部分将打印：#ServerName允许您设置发送回客户端的主机名

END部分将打印：＃响应来自的服务器）它将使用ServerName和#ServerName host.some_domain.com

，其间的print语句将在两个ServerName条目之间打印语句。

Answer 3

grep '^ServerName' your_file

或

perl -lne 'print if(/^ServerName[\s]+www/)' your_file

从httpd.conf导出域名

3 个答案: