Question

您好我有以下代码验证表单中是否有数据，然后我想确保在插入之前名称，电子邮件和地址不在我的数据库中...

你能告诉我在哪里搞砸了它，即使它是独特的数据也会抛出已经存在的错误

    if($_POST['formSubmit'] == "Submit") 
{
    $errorMessage = "";

    if(empty($_POST['formName'])) 
    {
        $errorMessage .= "<li>You forgot to enter a name!</li>";
    }
    if(empty($_POST['formEmail'])) 
    {
        $errorMessage .= "<li>You forgot to enter an email!</li>";
    }
    if(empty($_POST['formAddress'])) 
    {
        $errorMessage .= "<li>You forgot to enter your Address!</li>";
    }
    if(empty($_POST['formCity'])) 
    {
        $errorMessage .= "<li>You forgot to enter your City!</li>";
    }
    if(empty($_POST['formState'])) 
    {
        $errorMessage .= "<li>You forgot to enter your State!</li>";
    }
    if(empty($_POST['formZip'])) 
    {
        $errorMessage .= "<li>You forgot to enter your Zip!</li>";
    }

    $varName = $_POST['formName'];
    $varEmail = $_POST['formEmail'];
    $varAddress = $_POST['formAddress'];
    $varCity = $_POST['formCity'];
    $varState = $_POST['formState'];
    $varZip = $_POST['formZip'];
    $varDate = $_POST['formDate'];

    if(empty($errorMessage)) 
    {
        $db = mysql_connect("localhost","root","PASSWORD");
        if(!$db) die("Error connecting to MySQL database.");
        mysql_select_db("FormData" ,$db);

        $dupesql = "SELECT * FROM formdata WHERE (name = '$varName' AND email = '$varEmail' AND address = '$varAddress')";

        $duperaw = mysql_query($dupesql);

        if($duperaw > 0) {
            echo ("$varName already exists in $varAddress \n");
        } 
        else {
        $sql = "INSERT INTO formdata (name, email, address, city, state, zip, submitDate) VALUES (".
                        PrepSQL($varName) . ", " .
                        PrepSQL($varEmail) . ", " .
                        PrepSQL($varAddress) . ", " .
                        PrepSQL($varCity) . ", " .
                        PrepSQL($varState) . ", " .
                        PrepSQL($varZip) . ", " .
                        PrepSQL($varDate) . ")";
        mysql_query($sql);

        header("location: index.php?success=1");
        exit();
        }
    }

}

Answer 1

使用mysql_num_rows($duperaw) > 0代替$duperaw > 0来检查您的查询是否返回了任何结果。

另外，请避免使用mysql_*功能。它们不再被维护，而是deprecated as of PHP 5.5.0。请阅读this post以获取更详细的说明。相反，请使用PDO或MySQLi并了解prepared statements。 This article可以帮助您确定要使用的MySQL API。

PHP表单重复数据删除插入之前

1 个答案: