我正在开发一个VBA脚本,该脚本可以处理大量的电子邮件地址,并标记那些被怀疑是错误的地址。
我想通过添加一个能够识别常见域名中的拼写错误的函数来改进例程,例如gmail,hotmail,msn,skynet等。我将在数组中列出这些常见显示名称。
字符串函数将查看输入的字符串是否看起来相似但与数组中的元素不同,如果是这种情况,则返回true作为布尔值。
想法是发现错误的条目,例如:homtail,mns,slynet,hotmal,yahooo等。
不寻找脚本本身,寻找如何解决这个问题的灵感...
答案 0 :(得分:2)
你需要一个模糊的comarison - 有代码here将比较两个字符串,并根据它们的接近程度给你一个从0到1的分数。您可以决定自动替换它们的接近程度。
示例结果:
server text fuzzy score ------- -------- ----------- hotmail hotmale 0.7619048 hotmail hot 0.4285714 hotmail notmail 0.8571429 hotmail NotEvenClose 0.1944444 hotmail hotmail 1 hotmail yellow 0.0952381 hotmail homtail 0.7142857
源代码已在GNU Lesser GPL下发布
如果链接腐烂,请输入以下代码:
Public Function Fuzzy(ByVal s1 As String, ByVal s2 As String) As Single
Dim i As Integer, j As Integer, k As Integer, d1 As Integer, d2 As Integer, p As Integer
Dim c As String, a1 As String, a2 As String, f As Single, o As Single, w As Single
'
' ******* INPUT STRINGS CLEANSING *******
'
s1 = UCase(s1) 'input strings are converted to uppercase
d1 = Len(s1)
j = 1
For i = 1 To d1
c = Mid(s1, i, 1)
Select Case c
Case "0" To "9", "A" To "Z" 'filter the allowable characters
a1 = a1 & c 'a1 is what remains from s1 after filtering
j = j + 1
End Select
Next
If j = 1 Then Exit Function 'if s1 is empty after filtering
d1 = j - 1
s2 = UCase(s2)
d2 = Len(s2)
j = 1
For i = 1 To d2
c = Mid(s2, i, 1)
Select Case c
Case "0" To "9", "A" To "Z"
a2 = a2 & c
j = j + 1
End Select
Next
If j = 1 Then Exit Function
d2 = j - 1
k = d1
If d2 < d1 Then 'to prevent doubling the code below s1 must be made the shortest string,
'so we swap the variables
k = d2
d2 = d1
d1 = k
s1 = a2
s2 = a1
a1 = s1
a2 = s2
Else
s1 = a1
s2 = a2
End If
If k = 1 Then 'degenerate case, where the shortest string is just one character
If InStr(1, s2, s1, vbBinaryCompare) > 0 Then
Fuzzy = 1 / d2
Else
Fuzzy = 0
End If
Else '******* MAIN LOGIC HERE *******
i = 1
f = 0
o = 0
Do 'count the identical characters in s1 and s2 ("frequency analysis")
p = InStr(1, s2, Mid(s1, i, 1), vbBinaryCompare)
'search the character at position i from s1 in s2
If p > 0 Then 'found a matching character, at position p in s2
f = f + 1 'increment the frequency counter
s2 = Left(s2, p - 1) & "~" & Mid(s2, p + 1)
'replace the found character with one outside the allowable list
'(I used tilde here), to prevent re-finding
Do 'check the order of characters
If i >= k Then Exit Do 'no more characters to search
If Mid(s2, p + 1, 1) = Mid(s1, i + 1, 1) Then
'test if the next character is the same in the two strings
f = f + 1 'increment the frequency counter
o = o + 1 'increment the order counter
i = i + 1
p = p + 1
Else
Exit Do
End If
Loop
End If
If i >= k Then Exit Do
i = i + 1
Loop
If o > 0 Then o = o + 1 'if we got at least one match, adjust the order counter
'because two characters are required to define "order"
finish:
w = 2 'Weight of characters order match against characters frequency match;
'feel free to experiment, to get best matching results with your data.
'If only frequency is important, you can get rid of the second Do...Loop
'to significantly accelerate the code.
'By altering a bit the code above and the equation below you may get rid
'of the frequency parameter, since the order counter increments only for
'identical characters which are in the same order.
'However, I usually keep both parameters, since they offer maximum flexibility
'with a variety of data, and both should be maintained for this project
Fuzzy = (w * o + f) / (w + 1) / d2
End If
End Function
答案 1 :(得分:1)
你想做的是汉明码(或汉明距离) - 试试this