Question

CREATE TABLE #tmpCustomers(
[CustomerID] [int] NOT NULL,
[CustomerCode] [varchar](20) NULL,
[CustomerName] [varchar](128) NULL,
[LeftCount] [int] NULL,
[RightCount] [int] NULL,
[CreationDate][datetime]null,
)

DECLARE Customer_Cursor CURSOR FOR
SELECT customerid
FROM Customers
OPEN Customer_Cursor;

declare @left  int
declare @right int
declare @customerid int

FETCH NEXT FROM Customer_Cursor into @customerid
WHILE @@FETCH_STATUS = 0
BEGIN
  EXEC dbo.CountChildren @customerId,@left out,@right out

    insert into #tmpCustomers 
    select customerId,[CustomerCode],[CustomerName],(CONVERT(NUMERIC(38,2), Creationdate)),@left,@right from Customers where CustomerID=@customerid
   FETCH NEXT FROM Customer_Cursor into @customerid;
END;

select *, case when  leftcount>RightCount then RightCount else LeftCount end as Pairs from #tmpCustomers a
drop table #tmpCustomers
CLOSE Customer_Cursor;
DEALLOCATE Customer_Cursor;

以下是代码，此代码提供以下错误：

Msg 8115，Level 16，State 2，Line 24
将表达式转换为数据类型datetime的算术溢出错误。

请指导我如何设置。

Answer 1

我看到两件事看起来不对劲：

您正在将日期时间转换为数字值，从而为您提供自1900-01-01以来的天数（和小数天数）。我不明白你的代码中为什么这么做。
列在INSERT语句中没有正确排列。您正在将NUMERIC(18,2)值（由于CONVERT）插入整数字段，并将int值插入DATETIME字段。这可能就是您在结果中看到CreationDate的错误值的原因。

我怀疑你想要这样的东西：

INSERT INTO #tmpCustomers 
SELECT 
    customerId,
    [CustomerCode],
    [CustomerName],
    @left,
    @right, 
    Creationdate
FROM Customers 
WHERE CustomerID=@customerid

消息8115，级别16，状态2，行24（将表达式转换为数据类型datetime的算术溢出错误）

1 个答案: