有关SQLitedatabase的语法错误，何时是select * from

Question

这是错误

  

android.database.sqlite.SQLiteException：靠近“FROMfriendsWHERE”：   语法错误：，编译时：SELECT * FROMfriendsWHERE id！=？

这是我的代码

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id != ?",new String[]{Integer.toString(0)});

Answer 1

尝试

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id NOT LIKE ?",new String[]{Integer.toString(0)});

NOT LIKE用于do not have ? value in it

或者

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id <> ?",new String[]{Integer.toString(0)});

<>用于is not equal to ?