我正在用selenium webdriver开发一个用于单页webapp的Java框架,使用以下模式:PageObject,SlowLoadableComponent(责任链),PageFactory,HaveExpectedControls(每个页面都知道它应该包含哪些元素并通过它们返回它们。 getExpectedControls)
所以我创建并使用我的页面:
LoginPage loginPage = new LoginPage(driver, "http://mywebapp.com");
mainPage MainPage = new MainPage(driver, loginPage, "password");
mainPage.get(); //this method checks whether page .isLoaded(), if not - calls its .load() method and finally assert it .isLoaded()
for (WebElement element: mainPage.getExpectedControls()) {
assertTrue(element.isDisplayed);
}
我目前的目标是:测试用户在浏览我的网络应用时可以执行的所有“修补”。
一切都很简单,直到我到达我的webapp层次结构中更“深入”的页面...
我的网页可以表示如下
------------
|Login Page|
------------
->
|------------------------------
|LogoutLink
|---------------------------------
|mode: _ standart _ expert| __________________
|-------------------------| |SystemSettingsTab1|SystemSettingsTab2|SystemSettingsTab3
|*MainPage menu item | | ----------------------------------------
|*SomeOther menu item | | |
|... | | |
|*System menu item >->
|** Settings sub item >->
|... | |
|** OneMore sub item | |
以下是一些更多解释的“规则”:
First you get Login Page
Then (if loged in) you allways get 'MainPage menu item' (and 'standard' mode checked)
You allways see (so can click only what you see):
- only that sub-menu-items that are inside 'current' menu item page
- only that sub-menu-items-tabs that are:
- inside current sub-menu-item
- is correspondent to the current mode ('expert' mode allows more tabs)
Once clicked on any 'item' you allways get its first 'child item'
Then whatever you do you can:
- logout
- switch to any 'item' which you can see (check correspondent section above):
i.e.:
- switch to any other menu-item page by clicking on it
- switch to any of sub-menu-items of the current menu-item:
there is a special case for 'the first sub-menu-item':
you can get it by:
- clicking on its sub-menu-item link
- on its parent menu-item
- switch to any of sub-menu-item-tabs of current sub-menu-item
there is a special case for 'the first sub-menu-item-tab':
you can get it by:
- clicking on its sub-menu-item-tab link
- on its parent sub-menu-item
- on its parent menu-item
问题: 如何设计:
所有网页的类层次结构?
我可以在测试中浏览它们的方式吗?(特别是包括特殊情况,我可以通过多个链接获取某些页面)
答案 0 :(得分:0)
我认为以下将是一个简单而有效的解决方案,