我有一个ajax下拉框,如果选中将另一个字段添加到表单,这可以工作,但这个新字段不会随表单一起提交。有什么建议吗?
通过ajax调用findTest.php
<?php
$work = ($_GET['work']);
if ($work == "Work1") {
?>
<tr>
<td>New work1<input name="newWork1" size="20" type="text"/></td>
</tr> <?
} elseif ($work == "Work2") {
?>
<tr>
<td>New work<input name="newWork" size="20" type="text"/></td>
</tr><?
} elseif ($work == "Work3") {
?>
<tr>
<td>No work today</td>
</tr><?
}?>
test.php的
<?php
$page = '';
$answer = null; //clean start.
$Comments = $_POST['Comments'];
$new = $_POST['new'];
// Check if button name "Submit" is active, do this
if (isset($_POST['Submit'])) {
?>
<p align="center" id="infomessage">Test message <?= $_POST['Comments'] ?>
and <?= $_POST['new'] ?> or this should be
work2 <?= $_POST['newWork'] ?></p>
<? } ?>
<script language="javascript" type="text/javascript">
// Roshan's Ajax dropdown code with php
// This notice must stay intact for legal use
// Copyright reserved to Roshan Bhattarai - nepaliboy007@yahoo.com
// If you have any problem contact me at http://roshanbh.com.np
function getXMLHTTP() { //function to return the xml http object
var xmlhttp = false;
try {
xmlhttp = new XMLHttpRequest();
}
catch (e) {
try {
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
catch (e) {
try {
xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e1) {
xmlhttp = false;
}
}
}
return xmlhttp;
}
function getWorkDone(workId) {
var strURL = "findTest.php?work=" + workId;
var req = getXMLHTTP();
if (req) {
req.onreadystatechange = function () {
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
document.getElementById('workdiv').innerHTML = req.responseText;
} else {
alert("1 There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
</script>
<table id="meters" width="800" border="0" cellspacing=0 cellpadding=2>
<form name="meters" method="POST" action="test.php">
<tr>
<td width="200" align="right">Work Done:</td>
<td><select name="WorkDone" tabindex="14"
onchange="getWorkDone(this.value)">
<option value="Work1">Work1</option>
<option value="Work2">Work2</option>
<option value="Work3">Work3</option>
<option value="Other">Other</option>
</select>
</td>
</tr>
<tr>
<td></td>
<td><p id="workdiv">New Work<input name="newWork" size="20"
type="text"/></td>
</tr>
<tr>
<td width="200" align="right">Comments:</td>
<td><textarea name="Comments" tabindex="40" cols="40"
rows="4"><?= $_POST[Comments] ?></textarea></td>
</tr>
<tr>
<td colspan="7" align="center"><input type="submit" name="Submit"
class="button" value="Submit">
</td>
</tr>
</tr>
</table></form>
更新:新代码。
通过ajax调用findTest.php
<?php
if (isset($_GET['work'])) {
$work= $_GET['work'];
if ($work == "Noworktoday") {
echo "<tr><td>No work today</td></tr>";
} else {
echo "<tr><td>New ".$work."<br>";
echo "<input name=\"new".$work."\" type=\"text\"";
echo " size=\"20\" value=\"new".$work."\" />";
echo "</td></tr>";
}
}?>
和Test.php
<?php
$page = '';
$answer = null; //clean start.
if (isset($_POST['Comments'])) {
$Comments = $_POST['Comments']; } else {
$Comments = 'n/a'; }
if (isset($_POST['newWork1'])) {
$newWork = $_POST['newWork1']; } else {
$newWork = 'n/a'; }
if (isset($_POST['newWork1'])) {
$newWork = $_POST['newWork1']; } else {
$newWork = 'n/a'; }
if (isset($_POST['Submit'])) {
echo "message = ".$Comments."<br>";
echo "newWork1 = ".$newWork1."<br>";
echo "newWork2 = ".$newWork2."<br>";
echo "newOther = ".$newOther."<br>";
}
?>
<script language="javascript" type="text/javascript">
// Roshan's Ajax dropdown code with php
// This notice must stay intact for legal use
// Copyright reserved to Roshan Bhattarai - nepaliboy007@yahoo.com
// If you have any problem contact me at http://roshanbh.com.np
function getXMLHTTP() { //function to return the xml http object
var xmlhttp=false;
try{
xmlhttp=new XMLHttpRequest();
}
catch(e) {
try{
xmlhttp= new ActiveXObject("Microsoft.XMLHTTP");
}
catch(e){
try{
xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
}
catch(e1){
xmlhttp=false;
}
}
}
return xmlhttp;
}
function getWorkDone(workId) {
var strURL="findTest.php?work="+workId+"&new1="+"&$new";
var req = getXMLHTTP();
if (req) {
req.onreadystatechange = function() {
if (req.readyState == 4) {
// only if "OK"
if (req.status == 200) {
document.getElementById('workdiv').innerHTML=req.responseText;
} else {
alert("1 There was a problem while using XMLHTTP:\n" + req.statusText);
}
}
}
req.open("GET", strURL, true);
req.send(null);
}
}
</script>
<table id="meters" width="800" border="0" cellspacing=0 cellpadding=2>
<form name="meters" method="POST" action="test.php">
<tr>
<td width="200" align="right" >Work Done:</td>
<td><select name="WorkDone" tabindex="14" onchange="getWorkDone(this.value)">
<option value="">Select</option>
<option value="Work1">Work1</option>
<option value="Work2">Work2</option>
<option value="Work3">Work3</option>
<option value="Other">Other</option>
</select>
</td>
</tr>
<tr >
<td ></td>
<td ><p id="workdiv">New Work<input name="newWork" size="20" type="text" /></td>
</tr>
<tr>
<td width="200" align="right" >Comments:</td>
<td><textarea name="Comments" tabindex="40" cols="40" rows="4" ><?=$_POST[Comments]?></textarea></td>
</tr>
<tr>
<td colspan="7" align="center"><input type="submit" name="Submit" class="button" value="Submit">
</td>
</tr>
</tr>
</table>
</form>
UPDATE编辑加倍并将$ newWork更正为$ newWork1
<?php
$page = '';
$answer = null; //clean start.
if (isset($_POST['Comments'])) {
$Comments = $_POST['Comments']; } else {
$Comments = 'n/a'; }
if (isset($_POST['newWork1'])) {
$newWork1 = $_POST['newWork1']; } else {
$newWork1 = 'n/a'; }
if (isset($_POST['Submit'])) {
echo "message = ".$Comments."<br>";
echo "newWork1 = ".$newWork1."<br>";
echo "newWork2 = ".$newWork2."<br>";
echo "newOther = ".$newOther."<br>";}
?>
现在显示n / a但不是newWork1的值
答案 0 :(得分:1)
您已经修改了原始问题,我只能回复以前的问题。
重要的部分也是findTest.php
从此脚本中替换
document.getElementById('workdiv').innerHTML=req.responseText;
findTest.php
如何了解$_POST['newwork1']
<td>New work1<input name="newWork1" ... value="<?=$_POST['newwork1']?>" /></td>..
这必须来自GET / POST,但在你的GET中只有
strURL="findTest.php?work="+workId;
只有1个名为$ _GET ['work']的GET变量。
你使用这个变量(没有测试)
$work=$_GET['work'];
然后您将请求从$_GET
混合到$_POST['newwork1']
所以为什么不使用你的选择值来完成所有这些。
<强> test.php的强>
...
<select name="WorkDone" tabindex="14" onchange="getWorkDone(this.value)">
<option value="Work1">Work1</option>
<option value="Work2">Work2</option>
<option value="Noworktoday">No work today</option>
<option value="Other">Other</option>
</select>
...
<强> findTest.php 强>
if (isset($_GET['work'])) {
//for example : $work == "Work1"
$work=$_GET['work'];
if ($work=="Noworktoday") {
echo "<tr><td>No work today</td></tr>";
} else {
echo "<tr><td>New ".$work."<br>";
echo "<input name=\"new".$work."\" type=\"text\"";
echo " size=\"20\" value=\"new".$work."\" />";
echo "</td></tr>";
}
//<tr><td>New Work1<input name="newWork1" type="text" size="20" value="newWork1" /></td></tr>
更新
您无法看到自己的价值观,因为您没有echo
他们
你必须测试所有$_POST
$page = '';
$answer = null; //clean start.
if (isset($_POST['Comments'])) {
$Comments = $_POST['Comments']; } else {
$Comments = 'n/a';
}
if (isset($_POST['newWork1'])) {
$newWork1 = $_POST['newWork1']; } else {
$newWork1 = 'n/a';
}
....
依此类推所有可能的值
echo
您的变量
if (isset($_POST['Submit'])) {
?>
<p align="center" id="infomessage">Test message = <? echo $Comments; ?>
and = <? echo $newWork1; ?> or this should be
work2 = <? echo $newWork; ?></p>
<? } ?>
更新
我看不到实际的代码,所有可能的变量都需要if (isset ...
。在我的例子中,我只描述了两种可能性。你还需要例如
if (isset($_POST['newWork2'])) { ...
if (isset($_POST['newOther'])) { ...
等等!!并且只做简单的输出。
if (isset($_POST['Submit'])) {
echo "message = ".$Comments."<br>";
echo "newWork1 = ".$newWork1."<br>";
echo "newWork2 = ".$newWork2."<br>";
echo "newOther = ".$newOther."<br>";
}
并将其合乎逻辑
这是不合逻辑的Work2 assigned to newWork
!!!