这是显示问题的小提琴。 http://jsfiddle.net/Erk4V/1/
如果我在ng-if中有一个ng-model,那么该模型似乎无法正常工作。
我想知道这是一个错误还是我误解了正确的用法。
<div ng-app >
<div ng-controller="main">
Test A: {{testa}}<br />
Test B: {{testb}}<br />
Test C: {{testc}}<br />
<div>
testa (without ng-if): <input type="checkbox" ng-model="testa" />
</div>
<div ng-if="!testa">
testb (with ng-if): <input type="checkbox" ng-model="testb" />
</div>
<div ng-if="!someothervar">
testc (with ng-if): <input type="checkbox" ng-model="testc" />
</div>
</div>
</div>
答案 0 :(得分:216)
ng-if
指令与其他指令一样,创建子范围。请参阅下面的脚本(或this jsfiddle)
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.0rc1/angular.min.js"></script>
<script>
function main($scope) {
$scope.testa = false;
$scope.testb = false;
$scope.testc = false;
$scope.obj = {test: false};
}
</script>
<div ng-app >
<div ng-controller="main">
Test A: {{testa}}<br />
Test B: {{testb}}<br />
Test C: {{testc}}<br />
{{obj.test}}
<div>
testa (without ng-if): <input type="checkbox" ng-model="testa" />
</div>
<div ng-if="!testa">
testb (with ng-if): <input type="checkbox" ng-model="testb" /> {{testb}}
</div>
<div ng-if="!someothervar">
testc (with ng-if): <input type="checkbox" ng-model="testc" />
</div>
<div ng-if="!someothervar">
object (with ng-if): <input type="checkbox" ng-model="obj.test" />
</div>
</div>
</div>
因此,您的复选框会更改子范围内的testb
,但不会更改外部父范围。
注意,如果要修改父作用域中的数据,则需要修改对象的内部属性,就像我添加的最后一个div一样。
答案 1 :(得分:200)
您可以使用$parent
来引用父范围中定义的模型,如此
<input type="checkbox" ng-model="$parent.testb" />
答案 2 :(得分:47)
您可以使用ngHide (或ngShow)指令。它不像ngIf那样创建子范围。
<div ng-hide="testa">
答案 3 :(得分:6)
我们在许多其他情况下都有这个,我们内部决定总是有一个控制器/指令的包装器,这样我们就不需要考虑它了。 这是你的包装器的例子。
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.0rc1/angular.min.js"></script>
<script>
function main($scope) {
$scope.thisScope = $scope;
$scope.testa = false;
$scope.testb = false;
$scope.testc = false;
$scope.testd = false;
}
</script>
<div ng-app >
<div ng-controller="main">
Test A: {{testa}}<br />
Test B: {{testb}}<br />
Test C: {{testc}}<br />
Test D: {{testd}}<br />
<div>
testa (without ng-if): <input type="checkbox" ng-model="thisScope.testa" />
</div>
<div ng-if="!testa">
testb (with ng-if): <input type="checkbox" ng-model="thisScope.testb" />
</div>
<div ng-show="!testa">
testc (with ng-show): <input type="checkbox" ng-model="thisScope.testc" />
</div>
<div ng-hide="testa">
testd (with ng-hide): <input type="checkbox" ng-model="thisScope.testd" />
</div>
</div>
</div>
希望这有帮助, Yishay
答案 4 :(得分:3)
是的,ng-hide(或ng-show)指令不会创建子范围。
这是我的做法:
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.0rc1/angular.min.js"></script>
<script>
function main($scope) {
$scope.testa = false;
$scope.testb = false;
$scope.testc = false;
$scope.testd = false;
}
</script>
<div ng-app >
<div ng-controller="main">
Test A: {{testa}}<br />
Test B: {{testb}}<br />
Test C: {{testc}}<br />
Test D: {{testd}}<br />
<div>
testa (without ng-if): <input type="checkbox" ng-model="testa" />
</div>
<div ng-if="!testa">
testb (with ng-if): <input type="checkbox" ng-model="$parent.testb" />
</div>
<div ng-show="!testa">
testc (with ng-show): <input type="checkbox" ng-model="testc" />
</div>
<div ng-hide="testa">
testd (with ng-hide): <input type="checkbox" ng-model="testd" />
</div>
</div>
</div>
答案 5 :(得分:0)
你可以这样做,如果你想要一个代码笔,你的mod功能将完美让我知道
<div ng-repeat="icon in icons">
<div class="row" ng-if="$index % 3 == 0 ">
<i class="col col-33 {{icons[$index + n].icon}} custom-icon"></i>
<i class="col col-33 {{icons[$index + n + 1].icon}} custom-icon"></i>
<i class="col col-33 {{icons[$index + n + 2].icon}} custom-icon"></i>
</div>
</div>