Question

我有一个UIPickerController可以获取你的照片并允许你选择其中的一些，但是当我点击按钮激活应用程序崩溃时。

以下是我正在使用的代码：

在我的ViewDidLoad方法中：

pickerController = [[UIImagePickerController alloc] init];
pickerController.allowsEditing = NO;
pickerController.sourceType = UIImagePickerControllerSourceTypeSavedPhotosAlbum;

功能：

-(void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {
    [self dismissViewControllerAnimated:YES completion:nil];
    patientPicture = [info objectForKey:@"UIImagePickerControllerOriginalImage"];
    UIImageView *pictureView = (UIImageView *)[imageCell viewWithTag:777];
    pictureView.image = patientPicture;
    [_imgViewAdd reloadInputViews];
}

它被称为：

- (IBAction)addPicture:(id)sender {
    [self presentViewController:pickerController animated:YES completion:nil];
}

这很奇怪，因为我最近将我的应用程序更改为Ipad，虽然它在iPhone中它工作正常。当您单击NSLog中的按钮时，会出现此错误消息，我将其与之相关：

UIStatusBarStyleBlackTranslucent is not available on this device.

我怀疑这是人们常见的问题

提前致谢

Answer 1

尝试在popover中演示......

pickerController = [[UIImagePickerController alloc] init];
UIPopoverController *popOverController = [[UIPopoverController alloc] initWithContentViewController:pickerController];
popOverController.delegate = self;

并提出......

 [popOverController presentPopoverFromRect:yourframe inView:self.view permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

UIIMAGEPickerController使应用程序崩溃

1 个答案: