我已经创建了一个方法,可以将三个整数值转换为十六进制值(字符串),如下所示(P.S。:它尚未经过测试):
protected String convertRGBToHex(int r, int g, int b) {
String rFString, rSString, gFString, gSString, bFString, bSString, result;
int red, green, blue;
int rred, rgreen, rblue;
red = r / 16;
rred = r % 16;
if (red == 10) rFString = "A";
else if (red == 11) rFString = "B";
else if (red == 12) rFString = "C";
else if (red == 13) rFString = "D";
else if (red == 14) rFString = "E";
else if (red == 15) rFString = "F";
else rFString = String.valueOf(red);
if (rred == 10) rSString = "A";
else if (rred == 11) rSString = "B";
else if (rred == 12) rSString = "C";
else if (rred == 13) rSString = "D";
else if (rred == 14) rSString = "E";
else if (rred == 15) rSString = "F";
else rSString = String.valueOf(rred);
rFString = rFString + rSString;
green = g / 16;
rgreen = g % 16;
if (green == 10) gFString = "A";
else if (green == 11) gFString = "B";
else if (green == 12) gFString = "C";
else if (green == 13) gFString = "D";
else if (green == 14) gFString = "E";
else if (green == 15) gFString = "F";
else gFString = String.valueOf(green);
if (rgreen == 10) gSString = "A";
else if (rgreen == 11) gSString = "B";
else if (rgreen == 12) gSString = "C";
else if (rgreen == 13) gSString = "D";
else if (rgreen == 14) gSString = "E";
else if (rgreen == 15) gSString = "F";
else gSString = String.valueOf(rgreen);
gFString = gFString + gSString;
blue = b / 16;
rblue = b % 16;
if (blue == 10) bFString = "A";
else if (blue == 11) bFString = "B";
else if (blue == 12) bFString = "C";
else if (blue == 13) bFString = "D";
else if (blue == 14) bFString = "E";
else if (blue == 15) bFString = "F";
else bFString = String.valueOf(blue);
if (rblue == 10) bSString = "A";
else if (rblue == 11) bSString = "B";
else if (rblue == 12) bSString = "C";
else if (rblue == 13) bSString = "D";
else if (rblue == 14) bSString = "E";
else if (rblue == 15) bSString = "F";
else bSString = String.valueOf(rblue);
bFString = bFString + bSString;
result = "#" + rFString + gFString + bFString;
return result;
}
我的问题是:有没有办法可以将此字符串结果转换为int值,我可以这样使用:
view.setBackgroundColor(0xF82619);
或者是将字符串转换为int而不是将其转换为(无崩溃)的方法:
view.setBackgroundColor(result);
谢谢!
答案 0 :(得分:3)
假设你的字符串是
String col = "0xF82619";
尝试:
view.setBackgroundColor(Color.parseColor(col));
答案 1 :(得分:3)
要获得一个整数,你可以
int col = (0xff << 24) | ((r&0xff) << 16) | ((g&0xff) << 8) | (b&0xff);
更容易:
int col = Color.rgb(r, g, b);
答案 2 :(得分:2)
而不是将其转换为第一个字符串然后再转换为十六进制,而不是通过
将其转换为十六进制 Integer.valueOf(String.valueOf(n), 16);
它会提高代码的性能。