Question

在我的聊天应用程序中，我希望获得所有在线注册用户。所以每个人，而不仅仅是我的名单中的人，这是通过这个代码实现的：

- (void)xmppStream:(XMPPStream *)sender didReceivePresence:(XMPPPresence *)presence {
// a buddy went offline/online
NSString *presenceType = [presence type]; // online/offline
NSString *myUsername = [[sender myJID] user];
NSString *presenceFromUser = [[presence from] user];
if (![presenceFromUser isEqualToString:myUsername]) {
    if ([presenceType isEqualToString:@"available"]) {
        [_chatDelegate newBuddyOnline:[NSString stringWithFormat:@"%@@%@", presenceFromUser, @"chat.denederlandsewateren.nl"]];
    } else if ([presenceType isEqualToString:@"unavailable"]) {
        [_chatDelegate buddyWentOffline:[NSString stringWithFormat:@"%@@%@", presenceFromUser, @"chat.denederlandsewateren.nl"]];
    }
}
}

使用此代码，用户只能看到其他用户是朋友＆＃39;但我需要在此特定域上注册的所有用户。这可能与ejabberd有关吗？

Answer 1

- (void)getAllRegisteredUsers {

    NSError *error = [[NSError alloc] init];
    NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/disco#items' node='all users'/>"
                                                            error:&error];
    XMPPIQ *iq = [XMPPIQ iqWithType:@"get"
                                 to:[XMPPJID jidWithString:@"DOMAIN"]
                          elementID:[xmppStream generateUUID] child:query];
    [xmppStream sendElement:iq];
}

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
{
    NSXMLElement *queryElement = [iq elementForName: @"query" xmlns: @"http://jabber.org/protocol/disco#items"];

    if (queryElement) {
        NSArray *itemElements = [queryElement elementsForName: @"item"];
        NSMutableArray *mArray = [[NSMutableArray alloc] init];
        for (int i=0; i<[itemElements count]; i++) {

            NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue];
            [mArray addObject:jid];
        }



    }

Answer 2

我遇到了同样的问题，我也queryElement为nil。我已经更改了响应代码以查看 XML这样的内容：

- (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
{
//DDLogVerbose(@"%@: %@ - %@", THIS_FILE, THIS_METHOD, [iq elementID]);

//NSXMLElement *queryElement = [iq elementForName:@"query" xmlns: @"http://jabber.org/protocol/disco#items"];
NSXMLElement *queryElement = [iq elementForName:@"query" xmlns: @"jabber:iq:roster"];
NSLog(@"IQ: %@",iq);
if (queryElement) {
    NSArray *itemElements = [queryElement elementsForName: @"item"];
    NSMutableArray *mArray = [[NSMutableArray alloc] init];
    for (int i=0; i<[itemElements count]; i++) {

        NSString *jid=[[[itemElements objectAtIndex:i] attributeForName:@"jid"] stringValue];
        NSLog(@"%@",jid);
        [mArray addObject:jid];
    }
}

return NO; 
}

正如您可能会看到我已更改的内容是xmlns:从此xmlns: @"http://jabber.org/protocol/disco#items"到此xmlns: @"jabber:iq:roster"，这给了我用户列表。

我正在使用ejabberd，不确定这是否适用于所有其他XMPP服务器。

此外，我发现这给了我“好友”用户的列表，看起来如果你想要“全部”用户，你需要以管理员用户的身份进行查询。请查看此链接以获取更多相关信息：https://www.ejabberd.im/node/3420

Answer 3

点击后，您无法轻松获得所有用户，完成此操作后，您必须按照step in the Example 1: everybody can see everybody else创建共享名册组，您将获得以下代表中的所有在线用户方法

- (void)xmppStream:(XMPPStream *)sender didReceivePresence:(XMPPPresence *)presence

iOS XMPP框架获得所有注册用户

3 个答案: