我正在尝试使用twitter api并获得回复
{"errors":[{"message":"Bad Authentication data","code":215}]}
我正在使用twitter site中的代码 我已经在模拟器中设置了Twitter帐户,并且还尝试了设备(也通过注销和重新登录多次重试)但我无法获得访问权限
[self.accountStore
requestAccessToAccountsWithType:twitterAccountType
options:NULL
completion:^(BOOL granted, NSError *error) {
if (granted) {
// getting granted false i.e. I am not reaching here
}
}
那么,我还需要做什么?任何评论,答案都表示赞赏。
答案 0 :(得分:4)
要回答自己的问题,可能对其他人有帮助。
虽然我在Twitter网站上使用示例https://dev.twitter.com/docs/ios/making-api-requests-slrequest但除 ACAccountStore 对象分配外,它的工作正常。
我只是在需要的地方重新分配ACAccountStore
。
- (void)fetchTimelineForUser:(NSString *)username
{
ACAccountStore *accountStore=[[ACAccountStore alloc]init];
// Step 0: Check that the user has local Twitter accounts
if ([self userHasAccessToTwitter]) {
// Step 1: Obtain access to the user's Twitter accounts
ACAccountType *twitterAccountType = [accountStore
accountTypeWithAccountTypeIdentifier:
ACAccountTypeIdentifierTwitter];
[accountStore
requestAccessToAccountsWithType:twitterAccountType
options:NULL
completion:^(BOOL granted, NSError *error) {
if (granted) {
// Step 2: Create a request
NSArray *twitterAccounts =
[accountStore accountsWithAccountType:twitterAccountType];
NSURL *url = [NSURL URLWithString:@"https://api.twitter.com"
@"/1.1/statuses/user_timeline.json"];
NSDictionary *params = @{@"screen_name" : username,
@"include_rts" : @"0",
@"trim_user" : @"1",
@"count" : @"1"};
SLRequest *request =
[SLRequest requestForServiceType:SLServiceTypeTwitter
requestMethod:SLRequestMethodGET
URL:url
parameters:params];
// Attach an account to the request
[request setAccount:[twitterAccounts lastObject]];
// Step 3: Execute the request
[request performRequestWithHandler:^(NSData *responseData,
NSHTTPURLResponse *urlResponse,
NSError *error) {
if (responseData) {
if (urlResponse.statusCode >= 200 && urlResponse.statusCode < 300) {
NSError *jsonError;
NSDictionary *timelineData =
[NSJSONSerialization
JSONObjectWithData:responseData
options:NSJSONReadingAllowFragments error:&jsonError];
if (timelineData) {
NSLog(@"Timeline Response: %@\n", timelineData);
}
else {
// Our JSON deserialization went awry
NSLog(@"JSON Error: %@", [jsonError localizedDescription]);
}
}
else {
// The server did not respond successfully... were we rate-limited?
NSLog(@"The response status code is %d", urlResponse.statusCode);
}
}
}];
}
else {
// Access was not granted, or an error occurred
NSLog(@"%@", [error localizedDescription]);
}
}];
}
}
答案 1 :(得分:-1)
我建议Parse.com更好,更轻松地实现Twitter和Facebook集成。你可以用几行代码来解决它们,其余的就是Parse。