Question

我也主要使用Scanner，也想尝试使用缓冲读卡器：继续我到目前为止所拥有的

import java.util.*;
import java.io.*;
public class IceCreamCone 
{
// variables
String flavour;
int numScoops;
Scanner flavourIceCream = new Scanner(System.in);

// constructor
public IceCreamCone()
{

}
// methods
public String getFlavour() throws IOexception 
{
    try{

    BufferedReader keyboardInput;
    keyboardInput = new BufferedReader(new InputStreamReader(System.in));
    System.out.println(" please enter your flavour ice cream");
    flavour  =  keyboardInput.readLine();
    return keyboardInput.readLine();
    }
    catch (IOexception e)
    {
        e.printStackTrace();
    }
}

我相当肯定会得到一个你可以说的int

Integer.parseInt(keyboardInput.readLine());

但如果我想要一个字符串

我该怎么办？

Answer 1

keyboardInput.readLine()已经返回一个字符串，所以你应该只做：

return keyboardInput.readLine();

（更新）

readLine方法抛出IOException。你要么抛出异常：

public String getFlavour() throws IOException {
   ...
}

或者你在方法中处理它。

public static String getFlavour() {
    BufferedReader keyboardInput = null;
    try {
        keyboardInput = new BufferedReader(new InputStreamReader(System.in));
        System.out.println(" please enter your flavour ice cream");
        // in this case, you don't need to declare this extra variable
        // String flavour = keyboardInput.readLine();
        // return flavour;
        return keyboardInput.readLine();
    } catch (IOException e) {
        // handle this
        e.printStackTrace();
    }
    return null;
}

如何从缓冲读卡器输入字符串？

1 个答案: