Question

这是数据如何给我，在一个对象w /元素由管道char分隔。

首先我需要将两个数组合并然后按字母顺序排序。以下示例是一个简化示例。但有些事情正在抛弃排序功能。结果很奇怪

carriersOne = ['St. Joseph\'s Medical Center | New York Health Care Insurance Company |    Some Other Company'];
carriersTwo = ['Advantage Care | Chicago Insurance Company | Hospital Insurance    Corporation'];

carriersOne = carriersOne[0].split('|');
carriersTwo = carriersTwo[0].split('|');

allCarriers = carriersOne.concat(carriersTwo);
allCarriers.sort();

count = allCarriers.length;

for(i=0;i<count;i++) {
alert(allCarriers[i]);
}

你得到的是：

  Chicago Insurance Company
  Hospital Insurance Corporation
  New York Health Care Insurance Company
 Some Other Company
Advantage Care
St. Joseph's Medical Center

w-t-bleep命令是什么？注意：如果您使用单个名称或可预测的名字和姓氏，它会合并并排序。

Answer 1

那是因为你没有剥离周围的空间，特别是领先的空间。排序已关闭，因为空格出现在任何字母之前。假设整行没有周围的空白区域，下面的代码应该修复它：

// split on pipe and surrounding white space
var splitRe = /\s*\|\s*/;

carriersOne = carriersOne[0].split(splitRe);
carriersTwo = carriersTwo[0].split(splitRe);

Answer 2

你需要修剪空格：

carriersOne = carriersOne[0].split('|').map(function(e){return e.replace(/^\s*/, '')});
carriersTwo = carriersTwo[0].split('|').map(function(e){return e.replace(/^\s*/, '')});

Answer 3

这是管道之间的空间。这是一个更加发达（更灵活）的解决方案。

http://jsfiddle.net/THEtheChad/3v7ss/

var carriersOne = ['St. Joseph\'s Medical Center | New York Health Care Insurance Company |    Some Other Company'];
var carriersTwo = ['Advantage Care | Chicago Insurance Company | Hospital Insurance    Corporation'];

var allCarriers = parseAndMerge(carriersOne, carriersTwo).sort();

var count = allCarriers.length;

allCarriers.forEach(function(carrier){
    alert(carrier);
});

function parseAndMerge(){
    var args = Array.prototype.slice.call(arguments)
      , collector = []
    ;//var

    args.forEach(function(arr){
        collector = collector.concat(arr[0].split('|').map(trim));
    });

    return collector;
}

function trim(string) { return string.trim() }

管道|之间的空格导致排序顺序不正确。尝试这样的事情：

http://jsfiddle.net/THEtheChad/LQxW8/

carriersOne = ['St. Joseph\'s Medical Center | New York Health Care Insurance Company |    Some Other Company'];
carriersTwo = ['Advantage Care | Chicago Insurance Company | Hospital Insurance    Corporation'];

carriersOne = normalize(carriersOne);
carriersTwo = normalize(carriersTwo);

allCarriers = carriersOne.concat(carriersTwo);
allCarriers.sort();

count = allCarriers.length;

for(i=0;i<count;i++) {
   alert(allCarriers[i]);
}

function normalize(arr){
  var carriers = arr[0].split('|')
    , i = carriers.length
  ;//var

    while(i--){
      carriers[i] = carriers[i].trim();  
    }

   return carriers;
}

Answer 4

问题是您在运营商名称中有前导空格。

     ["    Some Other Company", " Chicago Insurance Company ", " Hospital Insurance    Corporation", " New York Health Care Insurance Company ", "Advantage Care ", "St. Joseph's Medical Center "]

您可以移除前导空格并获得您正在寻找的结果：

carriersOne = ['St. Joseph\'s Medical Center | New York Health Care Insurance Company |    Some Other Company'];
carriersTwo = ['Advantage Care | Chicago Insurance Company | Hospital Insurance    Corporation'];

carriersOne = carriersOne[0].split('|');
carriersTwo = carriersTwo[0].split('|');

allCarriers = carriersOne.concat(carriersTwo);
allCarriers = allCarriers.map(
                 function(carrier){ 
                       // replace leading and trailing spaces
                       return carrier.replace(/^\s+|\s+$/g,'');
                 }
               );
allCarriers.sort();
console.log(allCarriers);

Answer 5

空格的ASCII为32，大写字符从65开始，小写字母从97开始。这就是为什么空格在A和a之前排序的原因。

您可能希望使用正则表达式或仅使用underscore.js

来修剪它

然后组合排序Javascript数组。获得不可预测的结果

5 个答案: