SQL结果中的PHP变量？

Question

所以，如果我说

$bike = 'Schwinn';

我是否可以使用select语句返回Your bike is a $bike.并且echo $statement为Your bike is a Schwinn.而无需额外解析？

Answer 1

通过在MySQL中使用CONCAT函数，您可以：

SELECT CONCAT('Your bike is a ', bike, '.') as 'Bike' FROM bicycles where bike = 'Schwinn'

DEMO