我正在尝试使用PDO预处理语句运行查询,该语句允许我让用户选择一个字段,然后输入该字段的值,并将其包含在我的查询中。
所以在这个基本查询中:
$sql = "SELECT LastName, FirstName FROM administrators WHERE Status=:Status ";
$stmt->bindParam(':Status',$Status, PDO::PARAM_STR);
效果很好。
但是我有一个搜索表单,允许用户选择显示FirstName,LastName的下拉列表,然后输入一个文本框来输入搜索词
$sql = "SELECT LastName, FirstName FROM administrators WHERE Status=:Status **AND FIELD = TERM**";
到目前为止,我还没有在网上找到任何好的例子。任何指导都表示赞赏。
我正在使用:
$params = array();
if (!empty($SearchField) && !empty($SearchFor))
{
$params['SearchField'] = $SearchField;
$params['SearchFor'] = $SearchFor;
}
但我收到错误: 致命错误:未捕获异常'PDOException',消息'SQLSTATE [42S22]:未找到列:1054'where子句'中的未知列'SearchField''
以下是我在表单中使用的代码:
<input id="searchtext" name="searchtext" type="text" placeholder="Search" value="<?php echo GetParam('searchtext'); ?>" />
<select name="searchby">
<option value="">Search By</option>
<option id="LastName" value="LastName" <?php if(GetParam('searchby') == 'LastName'){echo "selected='selected'";}?>>Last Name</option>
<option id="FirstName" value="FirstName" <?php if(GetParam('searchby') == 'FirstName'){echo "selected='selected'";}?>>First Name</option>
<option id="RoleName" value="RoleName" <?php if(GetParam('searchby') == 'RoleName'){echo "selected='selected'";}?>>Role Name</option>
</select>
<input type="submit" id="submit" name="command" value="search" />
这是我方法的代码:
public function GetAllUsers($Status = 'A',$SearchField = '',$SearchFor = '')
{
$db=DB::getInstance();
$sql = "SELECT administrators.AdminId, AdminEmail, LastName, FirstName, PrimaryPhone, CellPhone, administrators.Status, LoginDateTime, RoleName FROM administrators INNER JOIN permissions on permissions.AdminId=administrators.AdminId INNER JOIN roles on roles.RoleId=permissions.RoleId INNER JOIN sessions on sessions.AdminId=administrators.AdminId WHERE Status=:Status ";
$stmt=$db->prepare($sql);
$stmt->bindParam(':Status',$Status, PDO::PARAM_STR);
$stmt->execute();
return $stmt->fetchAll(PDO::FETCH_OBJ);
}
答案 0 :(得分:0)
您不能使用标识符的参数(表/列名称等)。您需要适当地清理这些并将它们注入您的查询字符串中。您仍然可以使用参数作为值。我可能还会找到一组可搜索的列。例如
// create a map of field key to column name mappings
$searchCols = array(
'fn' => 'FirstName',
'ln' => 'LastName'
);
在显示表单时,您可以使用它来生成选项
<select name="SearchField">
<?php foreach ($searchCols as $key => $label) : ?>
<option value="<?= htmlspecialchars($key) ?>"><?= htmlspecialchars($label) ?></option>
<?php endforeach ?>
</select>
现在使用它来构建您的查询
// you'll probably want some more validation around this
$searchField = $searchCols[$_POST['SearchField']];
$query = sprintf('SELECT LastName, FirstName FROM administrators WHERE Status = :Status AND `%s` = :searchTerm',
$searchField);
// prepare statement and bind status, etc ...
$stmt->bindParam(':searchTerm', $SearchFor);