我目前的代码如下。目前只有七个“ins”值,因此代码就足够了,但是从下个月开始,我被告知将有超过900个值!
我假设我可以使用某种类型的数组,而不是编写另外900个case语句。任何人都可以给我一个正确的推动方向吗?
Private Sub test()
Dim i As Long
Dim lr As Long
Dim ins As String
lr = Range("A" & Rows.Count).End(xlUp).Row
For i = 6 To lr
Select Case Cells(i, 20)
Case Is = ""
ins = Mid(Cells(i, 11), 14, 2)
Select Case Cells(i, 10)
Case "Inx", "ComInx"
Select Case Cells(i, 9)
Case "EINX"
Select Case ins
Case "LD"
Cells(i, 9).Value = "SR"
Case "GP"
Cells(i, 9).Value = "GAMA"
Case "AV"
Cells(i, 9).Value = "NU"
Case "AX"
Cells(i, 9).Value = "AXC"
Case "MZ"
Cells(i, 9).Value = "MZE"
Case "AD"
Cells(i, 9).Value = "AGD"
Case "AG"
Cells(i, 9).Value = "AG"
End Select
End Select
End Select
End Select
Next
End Sub
答案 0 :(得分:5)
我会为此使用字典对象。以下是基于您的观点的概念验证:
Private Sub test()
Dim i As Long
Dim lr As Long
Dim ins As String
Dim rngCases As Range, rngCases2 As Range, rngCase As Range
Dim dicCases As Dictionary
lr = Range("A" & Rows.Count).End(xlUp).Row
' rngCases stores the possible values of ins
' Here I assume they are stored in col 40
Set rngCases = Range(Cells(6, 40), Cells(lr, 40))
' rngCases2 stores the values you want to map for each value of ins.
' Here I assume they are stored in col 41
' No of entries = No of entries of rngCases
Set rngCases2 = Range(Cells(6, 41), Cells(lr, 41))
Set dicCases = New Dictionary
For Each rngCase In rngCases
If Not dicCases.Exists(rngCase.Value) Then
dicCases.Add Key:=rngCase.Value, Item:=rngCases2.Value
End If
Next rngCase
For i = 6 To lr
Select Case Cells(i, 20)
Case Is = ""
ins = Mid(Cells(i, 11), 14, 2)
Select Case Cells(i, 10)
Case "Inx", "ComInx"
Select Case Cells(i, 9)
Case "EINX"
' We simply need to refer to the mapped value of ins
If dicCases.Exists(ins) then
Cells(i, 9) = dicCases.Item(ins)
Else
' Throw an error or do something here
End If
End Select
End Select
End Select
Next
End Sub
要启用Dictionary
,请转到Tools->References
并选择Microsoft Scripting Runtime
。
我希望这能让你开始!