如何从一个文件中过滤不同的文件

Question

假设我想要从“流程”开始直到下一个“流程”的不同文件。 例如 输入文件

Process=0
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Process=1
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Process=2
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预期产出 File_0应该包含

Process=0
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File_1应包含

Process=1
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File_2应包含

Process=2
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Answer 1

查看Linux中的csplit命令。它在分隔符处拆分文本文件（可以用正则表达式定义）。

Answer 2

这将为每个部分创建文件并将文本输出到它们。如果在第一个“处理”之前有文本，则将其放入名为“Preamble”的文件中。

awk -F '[ =]' 'BEGIN {file="Preamble"} {if ($1 == "Process") file="File_"$2; print >> file}' inputfile

Answer 3

使用gawk / nawk（Solaris）

gawk -F"=" '/Process/{f=1;n=$2;print $0 > "File_"n;next}
f && /Process/{f=0} 
f&&NF{print $0 > "File_"n}
' file