如何通过类名获取类类型?

时间:2013-08-19 06:54:08

标签: c# reflection gettype

namespace Myspace
{
    public class MyClass
    {
    }
} //This class is in another file.

using Myspace;
static void Main(string[] args)
{
    Regex regexViewModelKey = new Regex(RegularExpr.ViewModelKeyPattern);
    string viewModel = regexViewModelKey.Match(match.Value).Value;
    //Now, vieModel is a string, and its value is "MyClass". So, I only know the class name, this is why I ask this question.

    //Now, I'm only allowed to use the string form of this class name to get its type.
    //I have tyied like this, but its no use.
    Type t = Type.GetType(viewModel);
    //it's return a null.

    //Then I tyied another method like this, but there is an exception when calling Assembly.Load
    Assembly assembly = Assembly.Load("Myspace");
    Type ty = assembly.GetType("Myspace" + viewModel);
}

我希望我的问题很明确。任何人都可以帮助我.THX 我只允许使用此类名的字符串形式来获取其类型。

大家好 我这样自己解决了这个问题。

{
      Type t = Type.GetType(string.Concat(viewModel, ",", "Myspace"));
}

3 个答案:

答案 0 :(得分:32)

只需使用函数typeof()。该参数只是该类名。

Type type = typeof(FIXProtoClientTest);

MSDN on typeof()

答案 1 :(得分:2)

一般来说,除非你用反射或界面做某事,否则几乎不需要进行类型比较。尽管如此:

如果您知道要与之比较的类型,请使用is或as运算符:

if( unknownObject is TypeIKnow ) { // run code here

as运算符执行强制转换,如果失败而不是异常,则返回null:

TypeIKnow typed = unknownObject as TypeIKnow;

如果您不知道类型并且只想要运行时类型信息,请使用 .GetType()方法:

Type typeInformation = unknownObject.GetType();



     // int is a value type
    int i = 0;
    // Prints True for any value of i
    Console.WriteLine(i.GetType() == typeof(int));

    // string is a sealed reference type
    string s = "Foo";
    // Prints True for any value of s
    Console.WriteLine(s == null || s.GetType() == typeof(string));

    // object is an unsealed reference type
    object o = new FileInfo("C:\\f.txt");
    // Prints False, but could be true for some values of o
    Console.WriteLine(o == null || o.GetType() == typeof(object));

 // Get the type of a specified class.
                Type myType1 = Type.GetType("System.Int32");
                Console.WriteLine("The full name is {0}.", myType1.FullName);
                // Since NoneSuch does not exist in this assembly, GetType throws a TypeLoadException.
                Type myType2 = Type.GetType("NoneSuch", true);
                Console.WriteLine("The full name is {0}.", myType2.FullName);

    // FileSystemInfo is an abstract type
    FileSystemInfo fsi = new DirectoryInfo("C:\\");
    // Prints False for all non-null values of fsi
    Console.WriteLine(fsi == null || fsi.GetType() == typeof(FileSystemInfo));

答案 2 :(得分:0)

如果您使用完全限定的类名,包括其命名空间,那么您的行Type.GetType(model)将起作用。

此外,如果它与进行调用的代码位于不同的程序集中,则当引用的程序集对象是包含该类型的程序集的实例时,应使用Assembly.GetType(typeName)。