我正在尝试使用给定字符的Pango渲染位图,在本例中为字母“T”。我认为这应该有用,但它只是打印出垃圾..
在此代码中,gtk_window
已初始化为GTK窗口。
int width, height;
PangoLayout *layout = gtk_widget_create_pango_layout(gtk_window, "T");
PangoFontDescription *fontdesc = pango_font_description_from_string("Terminus 12");
pango_layout_set_font_description (layout, fontdesc);
pango_layout_get_pixel_size (layout, &width, &height);
GdkPixmap *temp_pixmap = gdk_pixmap_new(NULL, width, height, 24) ;
GdkGC *gc = gdk_gc_new(temp_pixmap);
gdk_draw_layout( temp_pixmap, gc, 0, 0, layout) ;
GdkColormap *cmap = gdk_colormap_get_system() ;
GdkPixbuf *temp_pixbuf = gdk_pixbuf_get_from_drawable(NULL, temp_pixmap,
cmap, 0, 0, 0, 0, width, height);
int n_channels = gdk_pixbuf_get_n_channels (temp_pixbuf);
int rowstride = gdk_pixbuf_get_rowstride(temp_pixbuf);
guchar *pixels = gdk_pixbuf_get_pixels(temp_pixbuf);
int i,j;
for (j=0; j<height; j++) {
for (i=0; i<(width*n_channels); i++) {
printf("%02x ",
*(pixels + i + j*rowstride));
}
printf("\n");
}
每次输出都不同,但是一个例子:
dd 24 f8 dd 24 f8 8f 28 28 8f 28 28 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 fc 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
ef 14 ce 00 00 00 d0 00 20 00 00 00 ef 02 02 d0 00 01 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 fc 00 00 00 00 00 ef 02 02 00 03 40 00 00 b9 00 00 c8
00 00 01 00 00 07 00 00 07 00 00 00 00 00 02 00 00 00 00 00 d0 00 00 c8
00 00 01 00 00 00 00 00 03 00 00 00 00 00 00 00 00 00 00 00 04 00 00 00
00 00 04 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0e 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 12 ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 7a 4e 00 00 00 01 00 00 00 00 00 00 00 00 00 01 ff ff ff ff ff ff
ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
这看起来不像字母“T”!
知道我做错了什么吗?谢谢!
答案 0 :(得分:3)
好的,我明白了。我需要正确设置颜色,并在使用gdk_draw_rectangle
绘图之前清除区域:
PangoLayout *layout = gtk_widget_create_pango_layout(me->gtk_window, "T");
int width, height;
PangoFontDescription *fontdesc = pango_font_description_from_string("Sans 10");
pango_layout_set_font_description (layout, fontdesc);
pango_layout_get_pixel_size (layout, &width, &height);
GdkPixmap *temp_pixmap = gdk_pixmap_new(NULL, width, height, 24);
GdkGC *gc = gdk_gc_new(temp_pixmap);
GdkColor white = {0,0xFF00,0xFF00,0xFF00};
GdkColor black = {0,0,0,0};
GdkColormap *cmap = gdk_gc_get_colormap(gc);
gdk_gc_set_rgb_fg_color(gc, &black);
gdk_gc_set_rgb_bg_color(gc, &white);
gdk_draw_rectangle(temp_pixmap, gc, TRUE, 0, 0, width, height);
gdk_gc_set_rgb_fg_color(gc, &white);
gdk_gc_set_rgb_bg_color(gc, &black);
gdk_draw_layout(temp_pixmap, gc, 0, 0, layout);
GdkPixbuf *temp_pixbuf = gdk_pixbuf_get_from_drawable(NULL, temp_pixmap,
cmap, 0, 0, 0, 0, width, height);
int n_channels = gdk_pixbuf_get_n_channels (temp_pixbuf);
int rowstride = gdk_pixbuf_get_rowstride(temp_pixbuf);
guchar *pixels = gdk_pixbuf_get_pixels(temp_pixbuf);
int i,j;
for (j=0; j<height; j++) {
for (i=0; i<(width*n_channels); i++) {
printf("%02x ",
*(pixels + i + j*rowstride));
}
printf("\n");
}
给了我:
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
c5 ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff ff e3
25 30 33 33 33 33 33 33 3d 68 ba f6 ff d8 86 4a 35 33 33 33 33 33 31 2a
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 0c 41 a7 f1 fe cc 66 1c 03 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00
答案 1 :(得分:0)
只是一些基本提示,还没有尝试过您的代码: