我正在制作一个小型CMS,在那里你可以有朋友,并在他们的墙上张贴。我正在创建一个页面,您可以在其中查看您朋友发布的所有帖子(在他们的个人资料中),但是,我无法正常运行。
表:朋友
+---------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------------+---------+------+-----+---------+----------------+
| friend_id | int(10) | NO | PRI | NULL | auto_increment |
| user1_id | int(10) | NO | | NULL | |
| user2_id | int(10) | NO | | NULL | |
| friends_since | int(10) | NO | | NULL | |
+---------------+---------+------+-----+---------+----------------+
表:profile_posts
+----------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------+---------+------+-----+---------+----------------+
| post_id | int(12) | NO | PRI | NULL | auto_increment |
| posted_user_id | int(12) | YES | | NULL | |
| user_id | int(12) | YES | | NULL | |
| date_posted | int(11) | YES | | NULL | |
| total_likes | int(12) | YES | | NULL | |
| users_liked | text | YES | | NULL | |
| total_dislikes | int(12) | YES | | NULL | |
| users_dislikes | text | YES | | NULL | |
| message | text | YES | | NULL | |
+----------------+---------+------+-----+---------+----------------+
基本上,如果我想确定用户是否在其个人资料上发布了状态,则表profile_posts中的posting_user_id和user_id列必须匹配(posting_user_id是用户发布的帖子的ID,而user_id是user_id是发布该消息的人的ID。
但是,我已多次尝试获取朋友的状态。
SELECT *
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON `pp`.posted_user_id = `pp`.user_id
WHERE
`f`.user1_id != 2 OR
`f`.user2_id != 2
ORDER BY `pp`.`date_posted` DESC
LIMIT 0,15;
(Hurray不工作!:D)
SELECT `f`.*,`pp`.*,
IF(`f`.user1_id=2, `f`.user2_id, `f`.user1_id) AS `uid`
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON `pp`.posted_user_id =`uid`
WHERE
`f`.user1_id = `uid` OR
`f`.user2_id = `uid`
ORDER BY `pp`.`date_posted` DESC
LIMIT 0,15;
我不确定如何诚实地做到这一点,它开始让我愤怒,因为我无法想象如何做到这一点。 :/
答案 0 :(得分:1)
没关系,想出怎么做。 :d
修改强>
SELECT
`f`.*,
`pp`.*,
`ai`.`name`,
`ai`.`lastname`
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON
`pp`.`posted_user_id` = `pp`.`user_id` AND
`pp`.`user_id` = `f`.user1_id OR
`pp`.`user_id` = `f`.user2_id
LEFT JOIN `account_info` AS `ai`
ON `ai`.`u_id` = `pp`.`user_id`
WHERE
`pp`.`user_id` = `pp`.`posted_user_id` AND
`f`.user1_id = 1 OR
`f`.user2_id = 1 AND
`pp`.`user_id` = `pp`.`posted_user_id`
GROUP BY `pp`.post_id
ORDER BY `pp`.date_posted DESC
LIMIT 0,20;
选择当前用户的朋友,然后抓取他们朋友的所有个人资料帖子,然后加入帐户信息表以获取姓名和其他信息。
我试图看看我是否可以让它更小,如果不是更好......