Question

我写一个简单的字符串加密和解密，用拆分字符串到两个var和increment assci代码，然后在字符串的左右交换。

当我加密这个文本=“这是测试”时这很好用，但是当加密时，utf char不会像这样的字符串=“تستتتتتتتتتتتتتت”

加密代码是：

JNIEXPORT jstring JNICALL Java_com_test_ndk_MainActivity_encrypt(JNIEnv* env, jobject thiz, jstring dec) {
const char *nativeString = (*env)->GetStringUTFChars(env, dec, 0);
char *newstr;
char *left;
char *right;
int decLenght = strlen(nativeString);
int middl = decLenght / 2;
int i;
newstr = substr(nativeString, 0, middl);
int lenght = strlen(newstr);
left = malloc(lenght);
for (i = 0; i < lenght; i++) {
    left[i] = newstr[i] + 1;
}
left[lenght] = '\0';
newstr = substr(nativeString, middl, decLenght - middl);
lenght = strlen(newstr);
right = malloc(lenght);
for (i = 0; i < lenght; i++) {
    right[i] = newstr[i] - 1;
}
right[lenght] = '\0';
strcat(right, left);
(*env)->ReleaseStringUTFChars(env, dec, nativeString);
return (*env)->NewStringUTF(env, right);
}

和解密代码是：

JNIEXPORT jstring JNICALL Java_com_test_ndk_MainActivity_decrypt(JNIEnv* env, jobject thiz, jstring enc) {
const char *nativeString = (*env)->GetStringUTFChars(env, enc, 0);
char *newstr;
char *left;
char *right;
int encLenght = strlen(nativeString);
int middl = encLenght / 2;
int i;
if (encLenght % 2 != 0) {
    middl++;
}
newstr = substr(nativeString, 0, middl);
int lenght = strlen(newstr);
left = malloc(lenght);
for (i = 0; i < lenght; i++) {
    left[i] = (char) ((int) newstr[i] + 1);
}
left[lenght] = '\0';
newstr = substr(nativeString, middl, encLenght - middl);
lenght = strlen(newstr);
right = malloc(lenght);
for (i = 0; i < lenght; i++) {
    right[i] = (char) ((int) newstr[i] - 1);
}
right[lenght] = '\0';
strcat(right, left);
(*env)->ReleaseStringUTFChars(env, enc, nativeString);
return (*env)->NewStringUTF(env, right);
}

substr函数：

char* substr(const char *source, unsigned int start, unsigned int end) {
return strndup(source + start, end);
}

有没有人有解决方案。

Answer 1

UTF-8对于操作并非易事。对于您的编码/解码，您可以使用GetStringChars()（或更有效但限制性更强的GetStringCritical()）并运行生成的16位 jchar 数组。

在android NDK jni中加密和解密utf8字符串

1 个答案: