显示通过ajax返回的数据作为链接

Question

我通过ajax将“id”和“data”传递给php。这是jquery ajax代码

1.$.ajax({//Make the Ajax Request
2.           type: "POST",
3.                url: "dbtryout2_2.php",
4.                data:datastr,
5.                success: function(arrayphp)
6.               {
7.                   //here iam displaying the returned data.
8.                   //I wanna display this data as link
9.                   //because on clicking on it I 
10.                  //again want to call another php script.
11.                 $(".searchby .searchlist").append(arrayphp); 
12.                            
13.                }
14.            });

15. I have not shown the php code.The code is working well.
16.BUT iam unable to display the data as link.I also want to give the data a "class name".
17.PLEASE if anybody know ...fix this problem

Answer 1

如果php返回的数据只是链接的标签，您可以使用以下代码：

$.ajax({//Make the Ajax Request
    type: "POST",
    url: "dbtryout2_2.php",
    data:datastr,
    success: function(arrayphp)
    {
        var link = $('<a href="#" class="my-class">' + arrayphp + '</a>');
        $(".searchby .searchlist").append(link); 

    }
});