我的程序中存在分段错误。这是我的代码
char buffer[5000]="";
memset(buffer,0,sizeof(buffer));
sprintf(buffer,"<?xml version=\"1.0\" encoding=\"utf-8\"?>\
<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\" xmlns:log=\"http://wsdlclass.wsdlcreat.sims.triesten.com\">\
<soap:Header>\
</soap:Header>\
<soap:Body>\
<log:saveMessBillingDetails>\
<log:userId>%s</log:userId>\
<log:billNo>%s</log:billNo>\
<log:billingAmount>%s</log:billingAmount>\
<log:billingDate>%s</log:billingDate>\
<log:messId>%s</log:messId>\
<log:itemId>%s</log:itemId>\
<log:ipAddress>%s</log:ipAddress>\
<log:schoolId>%s</log:schoolId>\
</log:saveMessBillingDetails>\
</soap:Body>\
</soap:Envelope>",
"00007", "152555", "42.00", "17-08-2013", 10, "CHKK", "10.10.1.164", 1);
答案 0 :(得分:6)
使用*printf*()
系列函数时,您需要注意转换说明符的数字和类型与格式“string”后面的参数匹配。
对sprintf()
的调用不是这种情况,因为只传递"%s"
,并且传入整数(需要"%d"
)。但参数的数量是正确的。
<强>更新强>
您的代码的正确且安全的版本可能是:
char buffer[5000]="";
int printed = snprintf(buffer, sizeof(buffer), "<?xml version=\"1.0\" encoding=\"utf-8\"?>\
<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\" xmlns:log=\"http://wsdlclass.wsdlcreat.sims.triesten.com\">\
<soap:Header>\
</soap:Header>\
<soap:Body>\
<log:saveMessBillingDetails>\
<log:userId>%s</log:userId>\
<log:billNo>%s</log:billNo>\
<log:billingAmount>%s</log:billingAmount>\
<log:billingDate>%s</log:billingDate>\
<log:messId>%d</log:messId>\
<log:itemId>%s</log:itemId>\
<log:ipAddress>%s</log:ipAddress>\
<log:schoolId>%d</log:schoolId>\
</log:saveMessBillingDetails>\
</soap:Body>\
</soap:Envelope>",
"00007", "152555", "42.00", "17-08-2013", 10, "CHKK", "10.10.1.164", 1);
if (printed >= sizeof(buffer))
fprintf(stderr, "The target buffer was to small.\n");
答案 1 :(得分:3)
将10
和1
更改为"10"
和"1"
,因为sprintf
的相应转化说明符为%s
,需要字符串。
或者您可以将相应的说明符从%s
更改为%d
。