从表中删除*不起作用

Question

我正在尝试从表中删除所有行，但它无效。当我做echo $mydb->error; 它给了我以下内容：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '* FROM messages where from_user = ? and id = ?'

     $user = 'currentuser';
 if (isset($_POST['delete'])) {
 if(!empty($_POST['id'])){
 $id =  $_POST['id']; 


 $mydb = new mysqli('localhost', 'root', '', 'database');
 $stmt = $mydb->prepare("DELETE * FROM messages where from_user = ?  and id = ? ");
 echo $mydb->error;
 $stmt->bind_param('ss', $user, $id);
 foreach  ($_POST['id'] as $id) {
$stmt->execute();
}
echo"The Message deleted permanently";
}
}

Answer 1

应该是

$stmt = $mydb->prepare("DELETE FROM messages WHERE from_user = ?  AND id = ? ");

我会很高兴使用mysqli_*函数而不是弃用mysql_*

另外，DELETE不应该有*;这不是正确的语法。

参考：

• https://dev.mysql.com/doc/refman/5.0/en/delete.html

*语法与SELECT：

一起使用

• https://dev.mysql.com/doc/refman/5.0/en/select.html

Answer 2

如果要删除用户的所有消息：

$stmt = $mydb->prepare("DELETE FROM messages where from_user = ?");
$stmt->bind_param('s', $user);
$stmt->execute();

如果您想从表中删除所有行（小心！）：

$stmt = $mydb->prepare("DELETE FROM messages");
$stmt->execute();