我正在改变我的问题这段代码中缺少什么或者错误当用户在textboxt
另一个texbox
输入内容时应该得到服务器时间但没有任何反应。我对编程缺乏经验。可以你帮忙
protected void Page_Load(object sender, EventArgs e)
{
Response.Expires = -1;
Response.Write(DateTime.Now.ToShortTimeString());
Response.End();
}
<script type="text/javascript">
function ajaxFunction() {
var xmlHttp;
xmlHttp = new XMLHttpRequest();
xmlHttp.onreadystatechange = function () {
if (xmlHttp.readyState == 4) {
document.getElementById("user").value = xmlHttp.responseText;
}
else {
document.getElementById("label").innerHTML = "wait";
}
xmlHttp.open("GET", "Default.aspx", true);
xmlHttp.send(null);
}
}
</script>
<title></title>
</head>
<body>
<input id="user" type="text" onkeyup="ajaxFunction()"/>
<p>
<input id="time" type="text" /></p>
<div id="label">
</div>
<p>
</p>
</body>
</html>
答案 0 :(得分:0)
您错误地调用了实际启动请求
function ajaxFunction() {
var xmlHttp;
xmlHttp = new XMLHttpRequest();
xmlHttp.onreadystatechange = function () {
if (xmlHttp.readyState == 4) {
document.getElementById("user").value = xmlHttp.responseText;
} // closes the if
else {
document.getElementById("label").innerHTML = "wait";
} // closes the else
} // closes the function() for onreadystatechange
// call the stuff
xmlHttp.open("GET", "Default.aspx", true);
xmlHttp.send(null);
}