我正在阅读带有plistib的itunes生成的xml播放列表。 xml有一个utf8标题。
当我用plistib读取xml时,我得到unicode(例如,'Name':u'Don \ u2019t You Remember')和字节字符串(例如,'Name':'Where Eagles Dare')。
标准建议是尽快使用正确的编码解码您所读取的内容,并在程序中使用unicode。但是,
unicode_string.decode('utf8')
失败(应该如此)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 3: ordinal not in range(128)
解决方案似乎是:
for name in names:
if isinstance(name, str):
name = name.decode('utf8')
# etc.
这是处理问题的正确方法吗?还有更好的方法吗?
我在Windows 7上。
编辑:
xml读取:
import plistlib
xml = plistlb.readPlist(fn)
for track in xml['Tracks']:
info = xml['Tracks'][track]
info['Name']
闲置生产:
u'Don\u2019t You Remember'
'Where Eagles Dare'
这是xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple Computer//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
<key>Major Version</key><integer>1</integer>
<key>Minor Version</key><integer>1</integer>
<key>Date</key><date>2013-08-14T15:04:27Z</date>
<key>Application Version</key><string>10.6.3</string>
<key>Features</key><integer>5</integer>
<key>Show Content Ratings</key><true/>
<key>Music Folder</key><string>file://localhost/C:/Users/rdp/Music/iTunes/iTunes%20Media/</string>
<key>Library Persistent ID</key><string>FE28CCACD9A36C34</string>
<key>Tracks</key>
<dict>
<key>1019</key>
<dict>
<key>Track ID</key><integer>1019</integer>
<key>Name</key><string>Where Eagles Dare</string>
<key>Artist</key><string>Iron Maiden</string>
<key>Album</key><string>Piece Of Mind</string>
<key>Genre</key><string>Rock</string>
<key>Kind</key><string>MPEG audio file</string>
<key>Size</key><integer>7372755</integer>
<key>Total Time</key><integer>370128</integer>
<key>Track Number</key><integer>1</integer>
<key>Year</key><integer>1983</integer>
<key>Date Modified</key><date>2009-10-07T21:11:31Z</date>
<key>Date Added</key><date>2008-02-07T16:04:15Z</date>
<key>Bit Rate</key><integer>153</integer>
<key>Sample Rate</key><integer>44100</integer>
<key>Play Count</key><integer>4</integer>
<key>Play Date</key><integer>3414416760</integer>
<key>Play Date UTC</key><date>2012-03-12T21:06:00Z</date>
<key>Artwork Count</key><integer>1</integer>
<key>Persistent ID</key><string>FE28CCACD9A383E5</string>
<key>Track Type</key><string>File</string>
<key>Location</key><string>file://localhost/D:/music/Iron%20Maiden/Piece%20Of%20Mind/01%20Where%20Eagles%20Dare.mp3</string>
<key>File Folder Count</key><integer>-1</integer>
<key>Library Folder Count</key><integer>-1</integer>
</dict>
<key>11559</key>
<dict>
<key>Track ID</key><integer>11559</integer>
<key>Name</key><string>Don’t You Remember</string>
<key>Artist</key><string>Adele</string>
<key>Album</key><string>21</string>
<key>Genre</key><string>Pop</string>
<key>Kind</key><string>MPEG audio file</string>
<key>Size</key><integer>6120028</integer>
<key>Total Time</key><integer>229511</integer>
<key>Track Number</key><integer>4</integer>
<key>Track Count</key><integer>11</integer>
<key>Year</key><integer>2011</integer>
<key>Date Modified</key><date>2012-11-17T10:50:31Z</date>
<key>Date Added</key><date>2012-12-19T16:03:46Z</date>
<key>Bit Rate</key><integer>199</integer>
<key>Sample Rate</key><integer>44100</integer>
<key>Artwork Count</key><integer>1</integer>
<key>Persistent ID</key><string>7130C888606FB153</string>
<key>Track Type</key><string>File</string>
<key>Location</key><string>file://localhost/D:/music/Adele/21/04%20-%20Don%E2%80%99t%20You%20Remember.mp3</string>
<key>File Folder Count</key><integer>-1</integer>
<key>Library Folder Count</key><integer>-1</integer>
</dict>
</dict>
<key>Playlists</key>
<array>
<dict>
<key>Name</key><string>short</string>
<key>Playlist ID</key><integer>30888</integer>
<key>Playlist Persistent ID</key><string>166746C6572B0005</string>
<key>All Items</key><true/>
<key>Playlist Items</key>
<array>
<dict>
<key>Track ID</key><integer>11559</integer>
</dict>
<dict>
<key>Track ID</key><integer>1019</integer>
</dict>
</array>
</dict>
</array>
</dict>
</plist>
答案 0 :(得分:1)
plistlib
的2.X实现中的一个错误。 Python 3中的plistlib
总是返回更好的unicode字符串。
但你必须忍受它:)所以你的问题的答案是肯定的。从plist
def safe_unicode(s):
if isinstance(s, unicode):
return s
return s.decode('utf-8', errors='replace')
value = safe_unicode(info['Name'])
我添加了errors='replace'
,以防字符串不是utf-8
编码的。如果无法解码,您将获得一堆\ufffd
个字符。如果您想要获得例外,请将其删除并使用e.decode('utf-8')
。
更新
当我尝试使用ElementTree时:
from xml.etree import ElementTree as et
tree = et.parse('test.plist')
map(lambda x: x.text, tree.findall('dict/dict/dict')[1].findall('string'))
哪位给了我:
[u'Don\u2019t You Remember',
'Adele',
'21',
'Pop',
'MPEG audio file',
'7130C888606FB153',
'File',
'file://localhost/D:/music/Adele/21/04%20-%20Don%E2%80%99t%20You%20Remember.mp3']
所以混合了unicode和字节串: - /