我使用QuickFixJ,设置中只有启动器。 我发送登录请求,接收响应,但它被视为登录请求,并发送另一个登录请求。
toAdmin:FIX.4.4:XXXX-> XXXX; M = 8 = FIX.4.49 = 7535 = A34 = 249 = XXXX52 = 20130816-11:55:25.26356 = XXXX98 = 0108 = 10141 = Y10 = 089
FixLog - OUTGOING - 8 = FIX.4.49 = 7535 = A34 = 149 = XXXX52 = 20130816-11:55:25.26356 = XXXX98 = 0108 = 10141 = Y10 = 088
FixLog - INCOMING - 8 = FIX.4.49 = 007735 = A49 = XXXX56 = XXXX52 = 20130816-11:55:25.73934 = 00000000198 = 0108 = 1010 = 021
FixLog - 推断ResetSeqNumFlag作为响应的序列号为1 重置请求
FixLog - 登录包含ResetSeqNumFlag = Y,重置序列号 到1
fromAdmin:FIX.4.4:XXXX-> XXXX; M = 8 = FIX.4.49 = 7735 = A34 = 00000000149 = XXXX52 = 20130816-11:55:25.73956 = XXXX98 = 0108 = 1010 = 181
FixLog - 收到登录
toAdmin:FIX.4.4:XXXX-> XXXX; M = 8 = FIX.4.49 = 7535 = A34 = 149 = XXXX52 = 20130816-11:55:25.90156 = XXXX98 = 0108 = 60141 = Y10 = 092
FixLog - OUTGOING - 8 = FIX.4.49 = 7535 = A34 = 149 = XXXX52 = 20130816-11:55:25.90156 = XXXX98 = 0108 = 60141 = Y10 = 092
启动登录请求
有人遇到过这样的问题,有什么建议吗?