如何以编程方式将ToggleButton添加到特定的listView

Question

我知道如何将ToggleButton添加到所有listView行。但是，如何将ToggleButton添加到一个特定的listView行？

我用listAdapter填充我的listView，如此

ListView mlistView = (ListView) findViewById(R.id.listViewSetting);
mlistView.setAdapter(new ArrayAdapter<String>(this,
          android.R.layout.simple_list_item_1,
          new String[] {"Rate @ME App", "Feedback", "Block", "Terms of Service", "Push Notifications", "Sign Out"}));

Answer 1

1. 创建包含togglebutton
的布局文件
2. 通过扩展适配器来创建customAdapter，例如ArrayAdapter
3. 覆盖getView（）方法
4. 实施viewHolder模式以提高性能
5. 向getView（）方法添加逻辑以处理togglebutton

这是一些伪代码

    @Override
    public View getView(final int position, final View convertView, final ViewGroup parent) {
         // Do inflation here, use a viewholder pattern to improve performance

         // Add logic to handle togglebutton, view being togglebutton
         if(items.get(position).equals(something){
            view.setVisibilty(View.Visible);
         }else{
             view.setVisibilty(View.GONE);
         }
     }