Question

我尝试使用此代码保存图像。它将图像保存在给定路径中，但不会获取文件名。我怎么能得到它？

@csrf_exempt
def upload_file(request):
    if request.method == 'POST':

        form = UploadFileForm(request.POST, request.FILES)

    if 'filename'  in request.FILES:
        filename = request.FILES['filename'].name
        if form.is_valid():
            handle_uploaded_file(request.FILES['file'])
            return HttpResponseRedirect('/user_profileform/')
    else:

        form = UploadFileForm()
    return render_to_response('user_profile.html', {'form': form })

def handle_uploaded_file(f):

    destination = open('media/filename', 'wb+')
    for chunk in f.chunks(): 
        destination.write(chunk)
    destination.close()

Answer 1

您似乎想重复使用文件名来保存文件，您可以尝试：

def handle_uploaded_file(f):
    filename = f.name  # get the name here
    destination = open('media/'+filename, 'wb+')
    for chunk in f.chunks(): 
        destination.write(chunk)
    destination.close()

在upload_file视图中，也存在错误：

@csrf_exempt
def upload_file(request):
    if request.method == 'POST':
        form = UploadFileForm(request.POST, request.FILES)

    if 'filename'  in request.FILES:
        # filename = request.FILES['filename'].name  # remove this line, you don't need it
        if form.is_valid():
            handle_uploaded_file(request.FILES['filename']) # should be filename here
    #.... your code ....

希望它有所帮助。

Answer 2

这可能是编码错误。您的POST是否编码为UTF-8？这意味着在HTML中有类似的东西：

<meta charset="UTF-8" />

如何在Django中从request.FILE获取文件名？

2 个答案: