#include <stdio.h>
#include <iostream>
using namespace std;
//char* b[6] = new char[6];
char a[6] = {'b','c','d','e','f','g'};
char c[6] = {'a','b','d','d','f','g'};
int main()
{
char d[][6]={*a,*c};
for (int x = 0 ; x < 1; x++)
{
for(int y = 0; y<6; y++)
{
char test = d[x][y];
cout << test <<"\n";
}
}
return 0;
}
此代码是C ++代码。我正在尝试创建一个存储char数组的类。然后有另一个char数组存储已声明的char变量。它编译得很好,但它不能正常工作。当程序试图打印值
时,它没有得到正确的值答案 0 :(得分:2)
可能是指一系列指针:
char *d[]={a,c};
答案 1 :(得分:1)
typedef std::vector<char> VectorChar;
typedef std::vector< VectorChar* > VectorVectorChar;
struct V
{
V() : _v{ '0', '1', '2' } {}
VectorChar _v;
};
int main(void)
{
V arrV[5];
VectorVectorChar vvc;
for ( auto& v : arrV )
vvc.push_back( &v._v );
// print them
for ( auto pV : vvc )
{
for ( auto c : *pV )
cout << c << ' ';
cout << '\n;
}
return 0;
}
答案 2 :(得分:0)
我从这个问题中理解,你想创建用于存储已经初始化的char数组的类。
#include <stdio.h>
#include <iostream>
char a[6] = {'b','c','d','e','f','g'}; // Initialized character array. MAX 6
// This class will hold char array
class Test {
public:
void setName(char *name);
const char* getName();
private:
char m_name[6]; // MAX 6 ( since you already initialized(MAX 6), So no need dynamic memory allocation. )
};
void Test::setName(char *name) {
strcpy(m_name, name); // Copy, already initialized array
}
const char* Test::getName() {
return m_name;
}
int main(int argc, char** argv) {
{
Test foobar;
foobar.setName( a ); // set the pointer which point to starting of the initialized array.
cout << foobar.getName();
return 0;
}
答案 3 :(得分:0)
char a[6] = {'b','c','d','e','f','\0'};
char c[6] = {'a','b','d','d','f','\0'};
char* d[]= {a,c};
for (int x = 0 ; x < 2; x++)
{
for(int y = 0; y < 6; y++)
{
char test = d[x][y];
cout << test << "\n";
}
}
return 0;