Question

{ 
    "hintsacross": 
    [ { "number":"1" , "hinttext":"Hurt", "hintsquare":"A1" }, 
      { "number":"5" , "hinttext":"Make a selection", "hintsquare":"A6" }, 
      { "number":"8" , "hinttext":"Frank", "hintsquare":"A10" }
    ] ,
    "hintsdown": 
    [ { "number":"1" , "hinttext":"First Greek letter", "hintsquare":"A1" },
      { "number":"2" , "hinttext":"Used footnotes", "hintsquare":"A2" }, 
      { "number":"3" , "hinttext":"Listened to", "hintsquare":"A3" }
    ] 
 }

由于某些原因，PHP的json_decode没有解码这个JSON。

提前致谢...

P.S。当第25行运行时，我收到错误：

$ temp = json_decode（$ obj-＆gt; hints，true）;

解析错误：语法错误， C：\ Program Files（x86）\ Zend \ Apache2 \ htdocs \ crosswords \ query.blockouts.php中的意外'hintsacross'（T_STRING）< / b>在线 25

我通过JSONlint验证了我的JSON，并且出现了解析错误。

Answer 1

它是无效的JSON。尝试在“hintsdown”之前添加逗号并重试json_decode。

{
    "hintsacross": [
        {
            "number": "1",
            "hinttext": "Hurt",
            "hintsquare": "A1"
        },
        {
            "number": "5",
            "hinttext": "Make a selection",
            "hintsquare": "A6"
        },
        {
            "number": "8",
            "hinttext": "Frank",
            "hintsquare": "A10"
        }
    ],
    "hintsdown": [
        {
            "number": "1",
            "hinttext": "First Greek letter",
            "hintsquare": "A1"
        },
        {
            "number": "2",
            "hinttext": "Used footnotes",
            "hintsquare": "A2"
        },
        {
            "number": "3",
            "hinttext": "Listened to",
            "hintsquare": "A3"
        }
    ]
}

Answer 2

   $ll="{ "hintsacross": [ { "number":"1" , "hinttext":"Hurt", "hintsquare":"A1" }, { "number":"5" , "hinttext":"Make a selection", "hintsquare":"A6" }, { "number":"8" , "hinttext":"Frank", "hintsquare":"A10" } ],
   "hintsdown": [ { "number":"1" , "hinttext":"First Greek letter", "hintsquare":"A1" }, { "number":"2" , "hinttext":"Used footnotes", "hintsquare":"A2" }, { "number":"3" , "hinttext":"Listened to", "hintsquare":"A3" } ] } "

    $ll = json_decode($ll);
    print_r($ll);

在

附近添加（，）逗号

],
   "hintsdown"

希望这会有所帮助

Answer 3

json的格式不正确。使用jsonlint.com进行检查。您将收到错误，如果json格式正确，您也会得到一条好消息。

Parse error on line 18:
...A10"        }    ]"hintsdown": [     
---------------------^
Expecting 'EOF', '}', ',', ']'

纠正json：

{
    "hintsacross": [
        {
            "number": "1",
            "hinttext": "Hurt",
            "hintsquare": "A1"
        },
        {
            "number": "5",
            "hinttext": "Make a selection",
            "hintsquare": "A6"
        },
        {
            "number": "8",
            "hinttext": "Frank",
            "hintsquare": "A10"
        }
    ],
    "hintsdown": [
        {
            "number": "1",
            "hinttext": "First Greek letter",
            "hintsquare": "A1"
        },
        {
            "number": "2",
            "hinttext": "Used footnotes",
            "hintsquare": "A2"
        },
        {
            "number": "3",
            "hinttext": "Listened to",
            "hintsquare": "A3"
        }
    ]
}

PHP json_decode JSON字符串无法解码

3 个答案: