我正在尝试学习一些新东西，并且一直想学习如何用PHP和mysql建立一个网站......
我发现这个简单的教程和样本文件可以用
http://css-tricks.com/php-for-beginners-building-your-first-simple-cms/
我正在尝试添加另一个在数据库中工作的表，但是当我尝试显示它时它不起作用。这是我得到和使用的代码：
<?php
class simpleCMS {
var $host;
var $username;
var $password;
var $table;
public function display_public() {
$q = "SELECT * FROM laptopvoltage ORDER BY created DESC LIMIT 3";
$r = mysql_query($q);
if ( $r !== false && mysql_num_rows($r) > 0 ) {
while ( $a = mysql_fetch_assoc($r) ) {
$lvmodel = stripslashes($a['lvmodel']);
$lvmanuf = stripslashes($a['lvmanuf']);
$lvvolt = stripslashes($a['lvvolt']);
$entry_display .= <<<ENTRY_DISPLAY
<div class="post">
<h2>
$lvmodel
</h2>
<p> !!!!!!this dont show upp!!!!!! - - - - >>>>>
$lvmanuf
</p><----------- WHY?
<p>
$lvvolt
</p>
</div>
ENTRY_DISPLAY;
}
} else {
$entry_display = <<<ENTRY_DISPLAY
<h2> This Page Is Under Construction </h2>
<p>
No entries have been made on this page.
Please check back soon, or click the
link below to add an entry!
</p>
ENTRY_DISPLAY;
}
$entry_display .= <<<ADMIN_OPTION
<p class="admin_link">
<a href="{$_SERVER['PHP_SELF']}?admin=1">Add a New Entry</a>
</p>
ADMIN_OPTION;
return $entry_display;
}
public function display_admin() {
return <<<ADMIN_FORM
<form action="{$_SERVER['PHP_SELF']}" method="post">
<label for="lvmodel">Title:lv model</label><br />
<input name="lvmodel" id="lvmodel" type="text" maxlength="150" />
<div class="clear"></div>
<label for="lvmanuf">Title:lv manu</label><br />
<input name="lvmanuf" id="lvmanuf" type="text" maxlength="150" />
<div class="clear"></div>
<label for="lvvolt">Title:lvvolt</label><br />
<input name="lvvolt" id="lvvolt" type="text" maxlength="150" />
<div class="clear"></div>
<input type="submit" value="Create This Entry!" />
</form>
<br />
<a href="display.php">Back to Home</a>
ADMIN_FORM;
}
public function write($p) {
if ( $_POST['lvmodel'] )
$lvmodel = mysql_real_escape_string($_POST['lvmodel']);
if ( $_POST['lvmanuf'] )
$lvmanuf = mysql_real_escape_string($_POST['lvvolt']);
if ( $_POST['lvvolt'] )
$lvvolt = mysql_real_escape_string($_POST['lvvolt']);
if ( $lvmodel && $lvmanuf && $lvvolt ) {
$created = time();
$sql = "INSERT INTO laptopvoltage VALUES('$lvmodel','$lvmanuf','$lvvolt','$created')";
return mysql_query($sql);
} else {
return false;
}
}
public function connect() {
mysql_connect($this->host,$this->username,$this->password) or die("Could not connect. " . mysql_error());
mysql_select_db($this->table) or die("Could not select database. " . mysql_error());
return $this->buildDB();
}
private function buildDB() {
$sql = <<<MySQL_QUERY
CREATE TABLE IF NOT EXISTS laptopvoltage (
lvmodel VARCHAR(150),
lvmanuf TEXT,
lvvolt VARCHAR(150),
created VARCHAR(100)
)
MySQL_QUERY;
return mysql_query($sql);
}
}
?>
它不会显示$lvmanuf。当字段显示在我的数据库中时，对此的任何帮助都会很棒。
答案 0 :(得分：0)
你可以看到我们已经在里面设置了我们的基本html文档并添加了一个脚本，现在我们制作的脚本将使我们指定的id中加载的文件在设置的ammount秒后消失，然后在body体内我们把这段代码放到了HTML中，
<span id="messages">
<?php include "constant.php"; ?>
</span>
这段代码包含给这个脚本的主要玩家首先带有id属性的span标签告诉我们的javascript我们想要在设定的秒数之后看不见的文本的id，接着是
<php include "constant.hpp"; ?>
它包含了我们制作的constant.php文档中的所有内容。
档案1
的index.php
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8" /><meta http-equiv="content-language" content="en-US" />
<title>MySQL Connection test</title>
<script type="text/javascript">
window.onload = function()
{
timedHide(document.getElementById('messages'), 10);
}
function timedHide(element, seconds)
{
if (element) {
setTimeout(function() {
element.style.display = 'none';
}, seconds*1000);
}
}
</script>
</head>
<body>
<span id="messages">
<?php include "constant.php"; ?>
</span>
</body>
</html>
这个第二个文件我不打算解释它，因为它会使这种方式变长，但这个文件是mysql数据库的连接文件。
您需要填写的唯一部分是
$ database_ip =“”; //数据库ip地址在引号内
$ database_port =“”; //数据库端口进入引号
$ database_name =“”; //数据库名称在引号内
$ database_admin_user =“”; // admin用户名在引号内
$ database_admin_pass =“”; //管理员密码在引号内
这会将您的网站连接到数据库。
文件2
constant.php
<?php
$database_ip = ""; //database ip adress goes inside quotes
$database_port = ""; //database port goes inside quotes
$database_name = ""; //database name goes inside quotes
$database_admin_user = ""; //admin username goes inside quotes
$database_admin_pass = ""; //admin password goes inside quotes
//do not modify anything past this point unless you know php well.
$database_link = null;
$database_defaults = array("127.0.0.1","3306","MySQL","root","");
$error_defaults = array("error_no_101" => "required field *IP is empty, using default parameters!",
"error_no_102" => "required field *PORT is empty, using default parameters!",
"error_no_103" => "required field *NAME is empty, using default parameters!",
"error_no_104" => "required field *USER is empty, using default parameters!",
"error_no_105" => "required field *PASS is empty, using default parameters!");
if(empty($database_ip)){
$database_ip = $database_defaults[0];
echo $error_defaults["error_no_101"] . "<br/>";
}
if(empty($database_port)){
$database_port = $database_defaults[1];
echo $error_defaults["error_no_102"] . "<br/>";
}
if(empty($database_name)){
$database_name = $database_defaults[2];
echo $error_defaults["error_no_103"] . "<br/>";
}
if(empty($database_admin_user)){
$database_admin_user = $database_defaults[3];
echo $error_defaults["error_no_104"] . "<br/>";
}
if(empty($database_admin_pass)){
$database_admin_pass = $database_defaults[4];
echo $error_defaults["error_no_105"] . "<br/>";
}
$database_link = mysqli_connect($database_ip, $database_admin_user, $database_admin_pass, $database_name);
if (!$database_link) {
die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
} else {
echo 'Success... ' . mysqli_get_host_info($database_link) . "\n";
}
mysqli_close($database_link);
?>
我这样做是为了帮助你修复你的代码，而不是教你语言的语法。
学习php的语法我建议你去这里：
这是官方的php网站文档，它教你正确编写php的方法，
http://www.php.net/manual/en/langref.php
如果您有订阅费用，也可以尝试这个地方：
对于HTML，你可以去：
http://www.w3schools.com/html/default.asp
如果您有订阅费用，也可以尝试这个地方：
http://www.lynda.com/HTML-tutorials/HTML-Essential-Training-2012/99326-2.html